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Alex17521 [72]
3 years ago
11

What is the multiplicative rate of change for the exponential function f(x) = 21 2

Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0
I’m not sure but you should search it up
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Simplify 6^3/6^2<br> A. 6<br> B. 1 1/2<br> C. 18<br> D. 256
MaRussiya [10]
The answer would be (A) 6
8 0
4 years ago
15. Solve by factoring: 3x? - 15x + 12 = 0
Lostsunrise [7]

The solution for that proplem is X=4,1

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3 years ago
Describe a sequence of transformations for which Quadrilateral AA is the image of Quadrilateral BB.
snow_tiger [21]
X =b b b and what is an answer is really is coy plane is x g y and yams ten
7 0
1 year ago
a school system is reducing the amount of dumpster loads of trash removed each week. in week 5, there were 40 dumpster loads of
murzikaleks [220]
Since it is given that the reduction in the amount of waste each week is linear, it is conclusive that these data are also in arithmetic sequence. First, determine the common difference (d)
                                 d = (a10 - a5) / (10 - 5)
Subsituting the known values,
                                d = (30 - 40) / 5 = -2
To determine any term (at) of the arithmetic sequence,
                            at = a1 + (n - 1) x d 
Solve for a1 by using either the given a5 or a10,
                            40 = a1 + (5 -1) x -2     ; a1 = 48
The equation becomes, 
                                 at = 48 + -2(n -1)
                               
4 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' − 2y = (t − 4), y(0) = 0
yulyashka [42]

Using the Laplace transform, the value o y' − 2y = (t − 4), y(0) = 0 is⇒y(t) = 0 e^-t + u(t -1)e^1-t

Laplace rework is an critical rework approach that is in particular useful in fixing linear normal equations. It unearths very huge applications in  regions of physics, electrical engineering, control optics, arithmetic and sign processing.

y' − 2y = (t − 4),

y(0) = 0

Taking the Laplace transformation of the differential equation

⇒sY(s) - y (0) + Y(s) = e-s

⇒(s + 1)Y(s) = (0+ e^-s)/s + 1

⇒y(t) = L^-1{0/s+1} + {e ^-s/s + 1}

⇒y(t) = 0 e^-t + u(t -1)e^1-t

The Laplace remodel method, the feature within the time area is transformed to a Laplace characteristic within the frequency domain. This Laplace feature will be inside the shape of an algebraic equation and it can be solved easily.

Learn more Laplace transformation here:-brainly.com/question/14487437

#SPJ4

4 0
1 year ago
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