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3 years ago

PLEASE HELP!!!!!!!!! Braniest!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

AC or A

Step-by-step explanation:

If you follow the letters it'll show you its AC

Alex Ar [27]3 years ago

6 0

Answer:

Step-by-step explanation: because the line ac is going directly through the square

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A local grocery store decides to offer a free piece of fresh fruit (banana or apple) to all shoppers in the produce department.

xxMikexx [17]

The generalization that can be made from this study is that: Given the choice of a banana or an apple, twice as many shoppers will select an apple.

<h3>How to arrive at the generalization.</h3>

More of the shoppers are said to select an apple from the group of shoppers who are to but either banana or apple.

Those buying an apple are two times the people buying the banana, hence we can conclude that twice as many shoppers would choose the apple over banana.

Read more on probability here: brainly.com/question/24756209

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2 years ago

Find the unit rate.<br> 6,460 liters in 323 minutes<br> liters per minute

Sloan [31]

Answer:

Step-by-step explanation:

6,460 divided by 323 = 20

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3 years ago

Read 2 more answers

On a particular airline, checked bags can weigh no more than 50 pounds. Sally packed 32 pounds of clothes and five identical gif

mel-nik [20]

Answer:

50-32*8

Step-by-step explanation:

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3 years ago

A system of equations is shown.

siniylev [52]

4x+20=5y
Divide 5 on both sides
so your answer would be
4/5x+4=y

x+15=3y
Divide 3 on both sides
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3x+5=y

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3 years ago

Write a coordinate proof for the following statement: Any triangle ABC formed so that vertex C is on the perpendicular bisector

AnnyKZ [126]

Answer:

Answer is contained in explanation.

Step-by-step explanation:

Description of visual:

I started with the first picture. This is a picture of triangle ABC.

Now I'm going to draw a line segment from vertex C such that it is a perpendicular bisector of AB.

Proof:

CM is a perpendicular bisectors of AB is a given.

From this we can concluded by definition of perpendicular angles that angle AMC and angle BMC are right angles.

Since angles AMC and BMC are right angles, then they are congruent to each other.

By the definition of bisector and since CM bisects AB, then AM is congruent to MB.

By the reflexive property, we have that CM is congruent to CM.

We can conclude the two triangles, triangle CMA and CMB, are congruent by SAS Postulate.

Since triangles CMA and CMB are congruent, we can conclude that their corresponding parts are congruent.

Since their corresponding parts are congruent, then we now know that side CA and side CB are congruent.

Since two sides of the triangle ABC are congruent to each other, namely side CA and side CB, then the triangle ABC is an isosceles triangle.

Setup for coordinate geometry proof:

M is the midpoint of AB since CM is a bisector of AB.

Since M is the midpoint of AB, then M is located at the coordinates $(\frac{0+b}{2},\frac{0+0}{2})=(\frac{b}{2},0)$ .

We found this point such that the length AM is equal to the length MB.

That is, the distance between A and M is the same as the distance between M and B.

Let's check.

$AM=\sqrt{(\frac{b}{2}-0)^2+(0-0)^2}$

$AM=\sqrt{(\frac{b}{2})^2+0}$

$AM=\sqrt{\frac{b^2}{4}}$

$AM=\frac{\sqrt{b^2}}{\sqrt{4}}$

$AM=\frac{b}{2}$

$MB=\sqrt{(b-\frac{b}{2})^2+(0-0)^2}$

$MB=\sqrt{(\frac{b}{2})^2+0}$

$MB=\sqrt{\frac{b^2}{4}}$

$MB=\frac{\sqrt{b^2}}{\sqrt{4}}$

$MB=\frac{b}{2}$

We have confirmed that AM=MB.

(Based on the picture, we could have taken a slightly easier route to calculate the distance between M and A, then the distance between B and M. They are both a horizontal distance. So $MB=b-\frac{b}{2}=\frac{b}{2}$ where as $AM=\frac{b}{2}-0=\frac{b}{2}$ .)

Now we also want to assume that the line segment CM is perpendicular to AB. I have drawn the base of the triangle on the x-axis so a vertical line would be perpendicular to it. Also this would make point $C=(c,d)=(\frac{b}{2},d)$ . The $y$ -coordinate is $d$ because we don't know how high above the $x$ -axis the point $C$ is.