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jenyasd209 [6]
3 years ago
7

A marketing firm is studying consumer preferences for winter fashions in four different months. From a population of women, 18-2

1 years of age, a random sample of 100 women was selected in January. Another random sample of 100 women was selected in March. Another random sample of 100 women was selected in June. Another random sample of 100 women was selected in September.
A) The sample size was 4.
B) The sample size was 100.
C) The sample size was 400.
D) The sample size was 1.
Mathematics
1 answer:
Sliva [168]3 years ago
4 0

Answer:

B) The sample size was 100

Step-by-step explanation:

Number of sample size in January = 100

Number of sample size in March   = 100

Number of sample size in June     = 100

Number of sample size in  September = 100

The average sample size for the study = (100 +100+100+100)/4  

                                                                =  400/4

                                                                = 100

So the average sample size for the study is 100 women between 18 to 21 years.

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Evaluate the following expressions if a = 2, b = 3, x = 4, and y = 5.<br> b^2+3(2x-y)
butalik [34]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<h2 /><h2>Answer: 18</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2><h2 />

First we need to substitute the value of the variable into the expression.

b^{2}+3(2x-y) = 3^{2} + 3 (2(4)-5) .

Now we need to solve 3^{2} + 3 (2(4)-5).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

3^{2} + 3 (2(4)-5)

First, calculate 3 to the power of 2 and get 9.

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Multiply 2 and 4 to get 8.

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7 0
2 years ago
Someone help I don’t understand
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Answer:

a)C

b)E

Step-by-step explanation:

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b) Picking a card that is not T. None of the 6 letters are T so the probablity of picking a card with no T is 1. So the answer is E.

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