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Liono4ka [1.6K]
3 years ago
9

How many times largeris the value 250,000 than 250

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:1,000

Step-by-step explanation:

250,000÷250=1,000

Hope that helps :)

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Which relationships have the same constant of proportionality between yyy and xxx as the equation 3y=27x3y=27x3, y, equals, 27,
Vera_Pavlovna [14]

Answer:

y=9x

y=\frac{18x}{2}

y=\frac{81x}{9}

Step-by-step explanation:

The given equation is

3y=27x

If we isolate y, we can find the constant

y=\frac{27x}{3}\\ y=9x

So, the constant is k=9.

Another proportions that have the same constant as the given equation are

y=9x

y=\frac{18x}{2}

y=\frac{81x}{9}

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3 years ago
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What is the range of this function (I NEED AN ANSWER RLLY FAST PLSSSS)
yaroslaw [1]

Answer:

d

Step-by-step explanation:

the first oval's domain and the second's range. so you just choose the choice that includes all the values in the ranger.

5 0
3 years ago
Please help!! I can’t figure this out
Rudiy27
Each room has 2 walls that are 4x10 = 40 square feet and 2 walls that are 8x10 = 80 square feet. So 80+80+40+40 = 240 square feet of wall will be painted per room.

We use 2 coats of paint so in effect, we double the area. Imagine laying one thin wall on top of the other. The amount of paint area used per room doubles from 240 to 480

There are 4 of these rooms so 4*480 = 1920

The total area we need to paint is 1920 square feet

Divide this over 32 to get 1920/32 = 60

Final Answer: 60
5 0
3 years ago
Dividing a decimals by a decimal like 2.4 divid by 16.4
aksik [14]
Well 2.4/ 16.4 is 6.9, but idk if that is what u were asking for

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4 years ago
a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to
gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

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