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NeX [460]
3 years ago
11

A large pump can drain an 80,000 gallon pool in 3 hours. With a smaller pump also operating, the job only takes 2 hours. How lon

g would it take the smaller pump to drain the pool by itself?
Mathematics
1 answer:
jekas [21]3 years ago
7 0
We know that

<span>A large pump can drain an 80,000 gallon pool------------>  in 3 hours
 X gallons---------------------------------------------------------> in 2 hour
X=2*80000/3----------> 53333.33 gallons in 2 hour

therefore
</span><span>the smaller pump in two hours drain an [80000-53333.33]=26666.67 gallons
</span><span>
if the </span>smaller pump drain 26666.67 gallons-----------------> in 2 hours
<span> 80000 gallons------------------------------------------------> X
X=80000*2/26666.67------> 6 hours

the answer is 
</span><span>the smaller pump to drain the pool by itself would take 6 hours</span><span>
</span><span>
</span>
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3 years ago
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Answer:

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lyudmila [28]

Answer:

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Answer:

  see attached

Step-by-step explanation:

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