First convert the rate into a decimal.
8/100=0.08
Next put all those numbers 15,000, 0.08, and 6 into the equation A=P(1+(rt)).
This is how you do it.
A=15,000(1+(0.08*6))
A=15,000(1+0.48)
A=15,000(1.48)
A=22,200
Answer:
The volume of the cart will be 24 ft^3
Step-by-step explanation:
The first thing we need to calculate for this question is the number of boxes that fill the entire cart.
A layer of boxes consists of 8 boxes.
The cart holds a maximum of 3 layers of boxes.
So, the total number of boxes held by the cart are:
Total boxes = number of layers * boxes per layer
Total boxes = 3 * 8
Total boxes = 24
Since each box has a volume of one cubic foot, the total volume of the cart will be:
Volume of cart = number of boxes * volume of each box
Volume of cart = 24 * 1
Volume of cart = 24 ft^3
Answer: No he would still have 4 leftovers
Step-by-step explanation: 64 divided by 6 equals 10 and the remainder of 4
(a) x = 4
First, let's calculate the area of the path as a function of x. You have two paths, one of them is 8 ft long by x ft wide, the other is 16 ft long by x ft wide. Let's express that as an equation to start with.
A = 8x + 16x
A = 24x
But the two paths overlap, so the actual area covered will smaller. The area of overlap is a square that's x ft by x ft. And the above equation counts that area twice. So let's modify the equation by subtracting x^2. So:
A = 24x - x^2
Now since we want to cover 80 square feet, let's set A to 80. 80 = 24x - x^2
Finally, let's make this into a regular quadratic equation and find the roots.
80 = 24x - x^2
0 = 24x - x^2 - 80
-x^2 + 24x - 80 = 0
Using the quadratic formula, you can easily determine the roots to be x = 4, or x = 20.
Of those two possible solutions, only the x=4 value is reasonable for the desired objective.
(b) There were 2 possible roots, being 4 and 20. Both of those values, when substituted into the formula 24x - x^2, return a value of 80. But the idea of a path being 20 feet wide is rather silly given the constraints of the plot of land being only 8 ft by 16 ft. So the width of the path has to be less than 8 ft (the length of the smallest dimension of the plot of land). Therefore the value of 4 is the most appropriate.
