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emmainna [20.7K]

3 years ago

13

Show if lines are parallel, perpendicular, or neitherY=10x-2-10x+y=4

2 answers:

notka56 [123]3 years ago

8 0

The lines are parallel bc if you change -10x+y=4 into y=10x+4 they will have the same slope of m=10x

mamaluj [8]3 years ago

6 0

Solve the second equation for y
-10x+y=4
y=10x+4

so we have the 2lines
y=10x-2
y=10x+4

both are written in slope intercept form do the coefficient of x is there slope. since both slopes are the same, namely 10, the two lines are parallel

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Gabriella was out at a restaurant for dinner when the bill came. She wanted to leave a tip of 24%. What number should she multip

lorasvet [3.4K]

Answer: 0.24

Step-by-step explanation:

You have to multiply the percent by its decimal form and then you multiply the decimal by the cost of the meal

3 0

3 years ago

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A jar contains 30 marbles. It has 10 red, 6 black and 14 green marbles. Two marbles are drawn, the first is not returned before

Basile [38]

<u>Answer:</u>

The correct answer option is P (both green) = 91 / 435

<u>Step-by-step explanation:</u>

We are given that in a jar containing 30 marbles, 10 are red, 6 are black and 14 are green.

Two marbles are drawn and the second one is drawn without returning the first marble and we are to find the probability of getting green marbles both time.

P (both green) = $\frac { 1 4 } { 3 0 } \times \frac { 1 3 } { 2 9 }$ = 91 / 435

6 0

4 years ago

Log16^*+log4^*+log2^*=7

ale4655 [162]

Answer:

$x = 16$

Step-by-step explanation:

Given

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Required

Solve for x

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Change base of 16 and base of 4 to base 2

$\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7$

Express 16 and 4 as 2^4 and 2^2 respectively

$\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7$

The above can be rewritten as:

$\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7$

$log_22 = 1$

So, we have:

$\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7$

$\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7$

Multiply through by 4

$4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4$

$log_2(x) + 2}log_2(x) + 4log_2(x) = 28$

$7log_2(x) = 28$

Divide through by 7

$\frac{7log_2(x)}{7} = \frac{28}{7}$

$log_2(x) = 4$

Apply the following law of logarithm:

<em>If </em> $log_ab = c$ <em> </em><em>Then </em> $b = a^c$ <em></em>

So, we have:

$x = 2^4$

$x = 16$

6 0

3 years ago

Will give Brainliest. Write a linear equation for this statement:

Llana [10]

Answer:

$H(d) = -9.5(d-1) + 100$

Step-by-step explanation:

Let $d_n$ denote the number of hits on day n, then:

$d_1 = 100, d_3 = 81$

we can calculate that over the 2 days, the number of hits decreased by 19.

Assuming this is a linear equation and not an exponential decay line, then the series equation would be: $d_n_+_1 = d_n - 9.5$

To write this as a linear equation, if H(d) is a function where d is the day starting from 1 and H(d) is the nubmer of hits on that day:

$H(d) = -9.5(d-1) + 100$

3 0

2 years ago

Read 2 more answers

I need help on my homework

emmainna [20.7K]

Same but what subject do you need help

8 0

3 years ago