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Zolol [24]
3 years ago
8

Someone help me please! :D

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0
The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:

90 + 140 + (x - 10) + (x - 20) = 360

Combine like terms:

230 + 2x - 30 = 360

200 + 2x = 360

200 - (200) + 2x = 360 - (200)

2x = 160

Divide both sides by 2:

2x/(2) = 160/(2)

x = 80
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9514 1404 393

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  a) BE = 5; DE = 6; EF = 4

  b) ∠EFC ≅ ∠DA.F ≅ ∠BDE  or  <em>b = e = f = i</em>

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Each short segment is the same length as the marked one it is parallel to.

  E is the midpoint of BC, so BE = EC = 5.

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