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Zolol [24]
3 years ago
8

Someone help me please! :D

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0
The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:

90 + 140 + (x - 10) + (x - 20) = 360

Combine like terms:

230 + 2x - 30 = 360

200 + 2x = 360

200 - (200) + 2x = 360 - (200)

2x = 160

Divide both sides by 2:

2x/(2) = 160/(2)

x = 80
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What is the straight-line distance between (2, -4) and (-3, 8) on a coordinate grid?
Scrat [10]
It is most likely 14 units so it would be A. I think.
6 0
3 years ago
A and B are supplementary angles. If A = (5x + 27)° and B = (5x – 7)º, then find the measure of angle A.​
vazorg [7]

Answer:

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

Step-by-step explanation

supplementary angle=180

(5x + 27)° +  (5x – 7)º=180

5x+27+5x-7=180

10x+20=180

10x=180-20

10x=160

x=160/10

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

107+73=180

3 0
3 years ago
Help please. i am desperate
Nana76 [90]

Answer:

lol

Step-by-step explanation:

whyyy u say that hahahahhaa

4 0
3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
Help me with this problem please i’m confused
Taya2010 [7]

Answer:

3rd

Step-by-step explanation:

If you know about linear eq. it's just a simple rule no worry

3 0
2 years ago
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