Answer:
<u>7.2 m</u>
Explanation:
In this scenario, the man possesses kinetic energy as he is in motion.
⇒ KE = 1/2mv²
His potential energy will be equal to the kinetic energy as per the law of conservation of energy.
So, 1/2mv² = mgh [potential energy]
⇒ v²/2 = gh
⇒ h = v²/2g
⇒ h = (12)²/2(10)
⇒ h = 144/20
⇒ h = <u>7.2 m</u>
Answer:
T = 2390 degree C
Explanation:
Given data:
Resistance 12 ohm
Temperature 20 degree C
we know that linear relation between the resistance and temperature is given as
where is resistance at and = coefficient of resistivity
SOLVING FOR
degree C
WE KNOW
T = 2370 + 20
T = 2390 degree C
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Answer:
a = 6.31 m/s²
Explanation:
a) The acceleration of the car can be found using the Newton's second law:
<u>Where:</u>
F: is the net force acting on the car
m: is the mass
a: is the acceleration of the car
W: is the weight of the car
θ: is the angle = 40.0°
g: is the gravity = 9.81 m/s²
Hence, the acceleration is:
Therefore, the acceleration of the car is 6.31 m/s².
I hope it helps you!
The energy to be dissipated is proportional to 1/2 m v^2 ie proportional to v^2 for the same car
<span>In turn F * d = work done. </span>
<span>F is constant ( same brakes) </span>
<span>so d is proportional to v^2 </span>
<span>if v is multiplied by 3 then d is multiplied by 3^2 = 9 </span>
<span>distance = 180m</span>