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Rom4ik [11]
3 years ago
11

You are selling candy bars for the school to

Mathematics
1 answer:
Strike441 [17]3 years ago
7 0

Answer:

200 bars

Step-by-step explanation:

$300 - $50 = the amount of money you still need, $250

250 dollars/$1.25 per bar = 200 bars you need to sell to get 300 dollars

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Hurry!
NARA [144]

Ans(a):

Given function is f(x)=\frac{3x-1}{x+4}

we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0

so let's solve

x+4≠0 for x

x≠0-4

x≠-4

Hence at x=4, function can't have solution.


Ans(b):

We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)

so we get:

g(x)=f(x)+4

g(x)=\frac{3x-1}{x+4}+4

We may simplify this equation but that is not compulsory.

Comparision:  

Graph of g(x) will be just 4 unit upward than graph of f(x).


Ans(c):

To find value of x when g(x)=8, just plug g(x)=8 in previous equation

8=\frac{3x-1}{x+4}+4


8-4=\frac{3x-1}{x+4}


4=\frac{3x-1}{x+4}


4(x+4)=(3x-1)


4x+16=3x-1


4x-3x=-1-16

x=-17

Hence final answer is x=-17

8 0
3 years ago
Simplify this (2x)^{3}
Margaret [11]

Answer:

8x^3

Step-by-step explanation:

(2x)3

=(2x)3

=2x*2x*2x

=8x^3

7 0
2 years ago
Find a rational number and an irrational number that are between 5.2 and 5.5. Include the decimal approximation of the irrationa
mote1985 [20]

Answer:

5.3

Step-by-step explanation:

3 0
2 years ago
Is 3.14 irrational or rational
mixas84 [53]

Answer:

rational

Step-by-step explanation:

3 0
3 years ago
A lock has a three number code made up of 17 numbers if none of the numbers are allowed to repeat how many different ways can yo
Marrrta [24]

Answer:

680

Step-by-step explanation:

Use the binomial coefficient where you choose k=3 numbers out of n=17 possible numbers and find the total amount of combinations since order does not matter:

\displaystyle \binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{17}{3}=\frac{17!}{3!(17-3)!}\\\\\binom{17}{3}=\frac{17!}{3!(14)!}\\\\\binom{17}{3}=\frac{17*16*15}{3*2*1}\\\\\binom{17}{3}=680

Thus, you can make 680 three-non-repeating-number codes

8 0
2 years ago
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