Answer:
Those who were able to keep 12 fishes
Step-by-step explanation:
Given
Total = 20 (each)
Required
Which was able to keep 3/5
First, we need to calculate 3/5 of the total number of fishes
Fish = 3/5 * 20
Fish = (3 * 20)/5
Fish = 60/5
Fish = 12
From the calculation above, only those who keep 12 of the 20 fishes were able to keep 3/5 of their fishes
Answer:
17.5%
Step-by-step explanation:
First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.
There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.
First, I'll calculate the probability for 15 success, given 30 trials.
30c15*0.4^15*0.6^15
Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)
Answer:
-26
Step-by-step explanation:
1. Replace the x with 6
2. Multiply -4 by 6 to get -24
3. Subtract 2 from -24 to get -26
-26 is the answer.