Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
The answer to your question is below this
Step-by-step explanation:
This equation is in Standard Form. To find the x and y intercepts, it is easier to convert it to slope-intercept form, or y = mx + b.
6x - y = 10
-y = -6x + 10
y = 6x - 10
In slope-interecept form, you can see that the y-int, b, is -10, the constant. To find x, set y to zero.
0 = 6x - 10
10 = 6x
10/6 = x
5/3 = x
Answer:
slope=5/6
Step-by-step explanation:
m=y2-y1/x2-x1
3-(-2)=5
2-(-4)=6
5/6
hope this helps :3
if it did pls mark brainliest
