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4 years ago

How do you factor 5x^4- 5x^2

Mathematics

1 answer:

Len [333]4 years ago

4 0

The greatest common factor is 5x^2 so:

5x^2(x^2-1) (now notice that the parenthetical term is the difference of perfect squares)

The rule for factoring difference of squares is: a^2-b^2=(a-b)(a+b) so:

5x^2(x+1)(x-1)

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I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

Dmitrij [34]

Answer:

$V = \frac{450L - 6 L^{3} }{10}$

Step-by-step explanation:

The volume of a cuboid can be determined simply by the formula: V= LWH

(where: L is length, H is height and W is width).

In this particular case the base is a square, which means the length and width are equal. Hence we can modify the equation of volume:

$V = L^{2} H$

Now we need to find the value of H in terms of L. For this we can develop the equation for cost incurred in building the storage shed. We find the area of each side of the cuboid, and then we multiply it by cost per square feet to find the total cost incurred; as shown below:

Area:

Base: $L$ × $L = L^{2}$

Roof: $L$ × $L = L^{2}$

Side: $4 H$ × $L = 4HL$ (we have considered all four sides)

Cost:

Base: 4 $L^{2}$

Roof: 2 $L^{2}$

Side: $2.50 * 4HL = 10 HL$

Total cost:

4 $L^{2}$ + 2 $L^{2}$ + 10 $HL$ = 450

We simplify this equation further:

6 $L^2$ + 10HL = 450

10HL = 450 - 6 $L^2$

$H = \frac{450- 6 L^2}{10L}$

We now have the value of H, which we can substitute in the formula of Volume we deduced earlier:

substituting $H = \frac{450-6L}{10L}$ in $V = L^{2} H$ :

$V = L^2$ × $\frac{450 - 6L }{10L}$

Simplifying it further:

$V = L$ × $\frac{450 - 6L}{10}$

$V= \frac{450L - 6L^3}{10}$ is the final answer.

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Question: it takes Nadeem 22 minutes to walk 1 kilometre. At this rate, approximately how long will it take Nadeem to walk 5 kil

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Time = 22 minutes
Initial distance = 1 km.
Rate = 1km/ 22m
Final distance = 5 km.

Final time = Rate * Final distance

= 22m * 5km

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What number(s) should be distributed -2(x -3)

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