Answer:
do the times first then the plus then minus last
Step-by-step explanation:
Answer:
1) The correct option is the third line
2) The correct option is the third line please see attached graph
Step-by-step explanation:
For the system of inequalities,
7·x > 21 or 6·x -9 < 21 we have;
7·x > 21
x > 21/3 = 3
x > 3
Also we have for 6·x -9 < 21 we have;
6·x -9 < 21
6·x < 21 + 9
6·x < 30
x < 30/6 = 5
x < 5
The representation of the region x > 3 and the region x < 5 on the number line consists of indicating points 3 and 5 with circles not filled to represent less than < and not less than or equal to ≤ and shading the potion of the number line in between the two points
Which gives the correct option as the third line which has an open circle at point 3 and 5
b) To graph the inequality v + 4 > 2 and 8·v - 20 ≤ 36
For the inequality v + 4 > 2, we have;
v > 2 - 4
v > - 2
For the inequality 8·v - 20 ≤ 36, we have;
8·v - 20 ≤ 36
8·v ≤ 36 + 20
8·v ≤ 56
v ≤ 56/8
v ≤ 7
The region representing v > -2 or v ≤ 7 on the number line consists of indicating points -2 with a circle (not filled) to represent less than < and point 7 with a filled circle to represent less than or equal to ≤ and shading the potion of the number line in between the two points
Which gives the correct option is the third line which has a closed circle at point -2 and an open circle at point 7
Answer:
1.65
Step-by-step explanation:
He pays 5 dollars for the magizine which is valued at 3.35 and receives 1.65
Answer:
your answer is C.
Step-by-step explanation:
y-27≥-13
+27 +27
y≥14
Answer:
The product of (-5·q·r) × (-2·p·q·r) × p·q is 10·q³·r²·p²
Step-by-step explanation:
The question relates to the rules of multiplication of variables and indices rules, and simplifification of an expression ;
The given expression is (-5·q·r) × (-2·p·q·r) × p·q
Therefore, we have;
(-5·q·r) × (-2·p·q·r) × p·q = (-5) × (-2) × q×q×q × r×r ×p×p = 10 × q³ × r² × p²
10 × q³ × r² × p² = 10·q³·r²·p²
∴ (-5·q·r) × (-2·p·q·r) × p·q = 10 × q³ × r² × p² = 10·q³·r²·p²
(-5·q·r) × (-2·p·q·r) × p·q = 10·q³·r²·p².