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Korvikt [17]
3 years ago
6

A card player selects a playing card from a well-shuffled deck of standard playing cards and sees if the card is a red card or n

ot. He keeps the card, and then makes another selection and sees if the card is a red card or not. He continues this process 10 times and counts the total number of red cards that he selects. Is this a binomial random variable? A. no since the total number of red cards in the deck is unknown at the start of the experiment B. no, since probabilities of drawing red cards do not remain the same from trial to trial C. yes since red cards are successes and he is counting the number of red cards drawn D. yes since a red card is a success and every other card is a failure
Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

A

Step-by-step explanation:

there could be no red cards inside

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Last Friday Adam had $22.33. Over the weekend he received some money for cleaning the attic he now has $32 how much money did he
defon

Answer:

9.67

Step-by-step explanation:

32-22.33=9.67

Hope it helps ;)

8 0
3 years ago
Read 2 more answers
5. Which step is included in the construction of inscribed polygons? (5 points)
RideAnS [48]

Answer:

Your answer is D

Step-by-step explanation:

Your welcome

5 0
3 years ago
What is the value of (-14⁰)-2<br> a -1/196<br> b 1/196<br>c 0 <br>d 1
natta225 [31]

Answer:

It is -1/196 for those who want the quick answer and not the one below me calling the person dumb which I reported BTW because it is unacceptable.

Step-by-step explanation:

I know i dont work for Brainly but i apologize for the person who was called dumb.

6 0
3 years ago
Solve This Using The Quadratic Formula: 3x^2+9x-6=0
aivan3 [116]
<h3>Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}</h3>

Step-by-step explanation:

3x^2 +9x -6=0                                x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}

\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}                     here a = 3 ,b = 9 and c= -6

\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}

\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}

\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}

Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}

4 0
3 years ago
Check out the photo for the question
Anestetic [448]

Answer:

50

Step-by-step explanation:

42/n³∑k²+12/n²∑k+30/n∑1

=42/n³[n(n+1)(2n+1)/6]+12/n²[n(n+1)/2]+30/n [n]

=7n(n+1)(2n+1)/n³+6n(n+1)/n²+30

=7(n+1)(2n+1)/n²+6(n+1)/n+30

=[7(2n²+3n+1)+6(n²+n)+30n²]/n²

=[14n²+21n+7+6n²+6n+30n²]/n²

=[50n²+27n+7]/n²

=[50+27/n+7/n²]

→50 as n→∞

because 1/n,1/n²→0 as n→∞

4 0
3 years ago
Read 2 more answers
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