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3 years ago

The square root of 5 less than twice a number is 7. Find the number.

Mathematics

1 answer:

densk [106]3 years ago

3 0

Answer:

4.618

Step-by-step explanation:

Let's use x to represent the number so we can write an equation to solve it.

'twice the number' is represented by 2x so we have our equation:

2x-5^0.5=7

(5^0.5 is just square root 5 because I can't do a square root symbol.)

Now we need to isolate the x term so:

2x-5^0.5+5^0.5=7+5^0.5

2x=7+5^0.5

Square root 5 = 2.236 (3dp)

2x=7+2.236

2x=9.236

2x/2=9.236/2

x=4.618

Hope this helped!

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bonufazy [111]

-30 1/4

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3 years ago

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Simplify 3√p^4q^6r^5

jeka94

Answer:

3p^2q^3r^2√r

Step-by-step explanation:

3√p^4q^6r^5

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3 years ago

The hard drive on your computer has a capacity of 160 gigabytes (GB). You have used 122 GB. You want to save some home videos to

QveST [7]

Capacity of the hard drive = 160 GB.

Used space = 122 GB.

Free space = 160 - 122 = 38 GB.

So, the size of the home video collection should be less than or equal to 38 GB.

If u is the amount of space used, then, u ≤ 38

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3 years ago

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Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12

irina [24]

Answer:

Part 1) The perimeter is $P=6\sqrt{6}\ cm$

Part 2) The diagonal is $d=\sqrt{30}\ cm$

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

$A=bh$

$A=12\ cm^2$

$bh=12$ ----> equation A

The base is twice the height

$b=2h$ ----> equation B

substitute equation B in equation A

$(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm$

Find the value of b

$b=2\sqrt{6}\ cm$

step 2

Find the perimeter of rectangle

The perimeter is given by

$P=2(b+h)$

substitute

$P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm$

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

$d^2=b^2+h^2$

substitute

$d^2=(2\sqrt{6})^2+(\sqrt{6})^2$

$d^2=30$

$d=\sqrt{30}\ cm$

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3 years ago

What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2

Alex73 [517]

Answer:

d=1

Step-by-step explanation:

$\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}$

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4} =\frac{-2}{d+2}$

Now make the denominators same

LCD: (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3(d+2)}{(d-4)(d+2)} =\frac{-2(d-4)}{(d+2)(d-4)}$

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1

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2 years ago

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