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Thepotemich [5.8K]
4 years ago
13

A parabola is given by the equation y = x2 + 4x + 4.

Mathematics
1 answer:
ryzh [129]4 years ago
4 0
Vertex is (-2,0)
Hope this helps!
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The box plots compare the number of calories in each snack pack of crackers and cookies.
Nikitich [7]

Answer:

4th statement is true.

Step-by-step explanation:

We have been two box plots, which represents the number of calories in each snack pack of crackers and cookies. We are asked to find the correct statement about our given box plots.

1. More packets of crackers have 80 calories than any other number of calories.

We can see that median of box plot representing calories of cookies is 80. This means that half of the packets of crackers have less than 80 calories and half of the packets have more than 80 calories, therefore, 1st statement is false.

2. The value 70 is an outlier for the number of calories in the cookie pack.

Since an outlier is 1.5 times the interquartile range.

IQR=Q_3-Q_1

\text{IQR of cookie packs}=105-90

\text{IQR of cookie packs}=15

\text{Lower outlier}=Q_1-(1.5*IQR)

\text{Lower outlier}=90-(1.5*15)

\text{Lower outlier}=90-22.5

\text{Lower outlier}=67.5

Since any number less than 67.5 will be an outlier and 70 is grater than 67.5, therefore, 70 is not an outlier in number of calories in cookie packs and 2nd statement is false.

3. The upper quartile of the cookie data is equivalent to the maximum in the cracker data.

We can see that upper quartile of cookie data is 105 and the maximum in cracker data is 100. Since 105 is greater than 100, therefore, 3rd statement is false.

4. The number of calories in each pack of cookies has a greater variation than the number of calories in each pack of crackers.

Since range and IQR are good measures of variation of box-plots, so we will find the range and IQR of our both box-plots.

We have already seen that IQR of cookie packs is 15.

\text{IQR of cracker packs}=85-75

\text{IQR of cracker packs}=10

\text{Range}=\text{Maximum value - Minimum value}

\text{Range of calories in cracker packs}=100-70

\text{Range of calories in cracker packs}=30

\text{Range of calories in cookie packs}=115-70

\text{Range of calories in cookie packs}=45  

We can see that the range of calories in cookie packs (45) is greater than range of calories in cracker packs (30) and IQR of calories in cookie packs (15) is greater than IQR of calories in cracker packs (10), therefore, 4th statement is true.

3 0
4 years ago
Read 2 more answers
An Amtrak train travels at 125 mile per hour. Convert the speed to miles per minute round to the nearest tenth
Tomtit [17]
To convert this you divide the speed by 60 since there's 60 minutes in an hour
125/60 = 2.0833....

Since you round the answer would be
2.1 miles per minute
6 0
3 years ago
Read 2 more answers
A contractor bought 10.8 ft squared of sheet metal. has used 2.1 ft squared so far and has ​$139.20 worth of sheet metal remaini
Anuta_ua [19.1K]

Answer:

7.1

Step-by-step explanation:

5 0
3 years ago
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PLS HELP ME ASAP!!!!!!!!!!!!!!
Anton [14]
The answer to that question is C
8 0
3 years ago
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While playing baseball, sofia takes note of the extreme vectors for which she bats. what is the angle between her two extreme ba
k0ka [10]

The angle between the two extreme vectors of Sofia bats is 74.60 degrees.

In this question,

The angle between two vectors will be deferred by a single point, which is called as the shortest angle at which we have to turn around one of the vectors to the position of co-directional with another vector.

The extreme vectors of Sofia bats are  \vec u = < -8, 12 > and \vec v = < -8, 12 >

The angle between the vectors is

\theta = cos^{-1} \frac{\vec u.\vec v}{||\vec u|| ||\vec v||}

The dot product is calculated as

\vec u. \vec v = (-8)(13)+(12)(15)

⇒ -104+180

⇒ 76

The magnitude can be calculated as

||\vec u|| = \sqrt{(-8 )^{2} +(12)^{2} }

⇒ \sqrt{64+144}

⇒ \sqrt{208}

||\vec v|| = \sqrt{(13 )^{2} +(15)^{2} }

⇒ \sqrt{169+225}

⇒ \sqrt{394}

Thus the angle between the vectors is

\theta = cos^{-1} \frac{76}{(\sqrt{208} )(\sqrt{394} )}

⇒ \theta = cos^{-1} \frac{76}{\sqrt{81952} }

⇒ \theta = cos^{-1} \frac{76}{286.27 }

⇒ \theta = cos^{-1} (0.2654)

⇒ \theta=74.60

Hence we can conclude that the angle between the two extreme vectors of Sofia bats is 74.60 degrees.

Learn more about angle between two vectors here

brainly.com/question/19726452

#SPJ4

5 0
2 years ago
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