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Vaselesa [24]
3 years ago
5

6n+6m-m-3n i dont understand that question

Mathematics
1 answer:
solmaris [256]3 years ago
5 0
6n + 6m - m - 3n = 6n - 3n + 6m - m = 3n + 5n

2m + 2m + 2n + n = 4m + 3n
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Please help with some probelms!
posledela
The answer here is A which is the first graph.
Remember that if a is negative in the equation y = ax^2 + bx + c, the parabola always opens downward. For vertex, its coordinates is always located on the first quadrant in which all values are positive.
3 0
3 years ago
Five years back, Michael's age was 2/3 the age of James. After ten years he will be 5/6 of the age of James. What are the equati
irakobra [83]
I find it easier to start from scratch and write out the equations, then compare them with the given equations.

Let m and j represent the ages of the two boys.  Then m-5=(2/3)(j-5)
Also, in ten years:  m+10 = (5/6)j.

Let's solve this system:  Mult the first eqn by 3 to remove the fraction:
3(m-5) = 2(j-5), or 3m - 15 = 2j -10.  Next, mult. the 2nd eqn by 6 to remove the fraction:  6m+60 = 5j.

Our two equations are (at this point)      3 m - 15 = 2j - 10 and
                                                                6m  +60  = 5j

Let's mult. the first equation by -2, so as to obtain the coefficient -6 for m:

-6m + 30 = -4j + 10
 6m + 60  = 5j
---------------------------
90 = j + 10, so j = 80 (wow!)

Let's now find m:  6m + 60 = 5(80), or    6m = 400+60 = 460

Then m = 76 2/3.

We must check our solution (m = 76 2/3, j = 80):

Let's subst. these values into     m-5=(2/3)(j-5)

Does 76 2/3 - 5 = (2/3)(80) - 10/3?

Does 76 2/3 - 15/3 = 160/3 - 10/3?

Does 76 - 15 = 160 - 10    No.  So something's wrong here.

Going back to the problem statement:

<span>x-5=2/3(y-5) and x+10=5/6(y+10)  seems correct!


Mike's age 5 years ago was x-5, and james' age 5 years ago was y-5.  The multiplier (2/3) is also correct.

Mikes age 10 years from now will be x+10, and james' y+10.

The first answer set is the correct one.</span>
7 0
3 years ago
A right pyramid with a square base has a base edge length of 24 feet and a slant height of 20 feet.
4vir4ik [10]

Answer:

10.583

Step-by-step explanation:

If the height = h

Distance between the slant edge to center is 24 Cos 45

Therefore

h^{2}  = 20^{2}  - (24 Cos 45)^{2}

h = \sqrt{400-288} = 10.583

8 0
3 years ago
Can someone help me ? I can’t seem to get it :/
ale4655 [162]
I believe it is c but im not positive
4 0
3 years ago
Solve the equation.<br> -5r-1=7r+5
Ksivusya [100]

Answer:

-1/2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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