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3 years ago

What is 0.46% of 80?

2 answers:

5 0

The answer is 0.368

Step 1. Our output value is 80.

Step 2. We need to represent the unknown value with x.

Step 3. From step 1, 80 = 100

Step 4 and Step 5: Similarity x = 0.46% and do 80 = 100% equals to x = 0.46%

Step 6 and step 7: 80/x = 100%/0.46%

Do it again but do it reciprocal of both sides. X/80 = 0.46/100

X=0.368 is the answer

likoan [24]3 years ago

4 0

The answer would be 0.368 because you would have to multiply 0.46% and 80 to get your answer, 0.368.

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Help with this I don't know how to solve please please please!!

likoan [24]

Answer:

212.5

Step-by-step explanation:

Here's a theorem about triangle areas.

If two similar triangles have sides in the ratio x:y,

then their areas are in the ratio x2:y2

The triangles have sides in the ratio:

LP/LN = 10/25

The two triangles have areas in the ratio 100:625 (4/25)

For every 4 in the small triangle, there are 25 in the larger triangle.

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3 years ago

How can i use decimal models to add decimals?

Vinil7 [7]

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3 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

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3 years ago

40$ to the markup rate of 65% what is the final price?

djyliett [7]

Answer:

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Step-by-step explanation:

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3 years ago

Which of the following sets of numbers could not represent the three sides of a triangle?

timama [110]

Answer:

Step-by-step explanation:

In order for the sides lengths to form a triangle, the sum of the shortest two must exceed the longest.

That will not be the case for ...

{13, 16, 30}

because 13 +16 = 29 < 30.

(13, 16, 30} could not form a triangle

For more on the subject, see ...

brainly.com/question/26258903

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2 years ago