n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
189
Step-by-step explanation:
Step 1: the output value is 105
x=1.8% 105=100 (1) x=1.8% (2)
Volume is calculated by multiplying (3/4)pi by the radius cubed
Start with the brackets. Then do 5 multiply 1 which is 5 then divide that 5 from 20 which gets you 4. Times the outside of the brackets with the inside which will give you the answer of 16
