Answer:
x = ln(21)/ ln(4), Decimal Form: 2.19615871
Step-by-step explanation:
This is pretty complex math for middle school with logarithms and what not. Make sure you typed the problem in correctly. If you did, I guess that's your answer.
Answer:
DG = 17
Step-by-step explanation:
DG and EF are similar so sides are same.
2x - 7 = x + 5
2x - x = 5 + 7
x = 12
So DG = 2x - 7
= 2(12) - 7
= 24 - 7
= 17
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
Answer: 8/9
Step-by-step explanation:
Taking the probability as
AA = 4/9 AB = 2/9 BA = 2/9 BB = 1/9
These spaces AA,AB,BA,BB is indicates who wins each game.
There is a 2/3 probability that A will win any particular game.
But considering that these events are independent events, the probability that A wins both games is 2/3 and 2/3 which equals to 4/9.
Therefore the probability that A wins at least one match would be 1 − P(BB).
And this gives 1 - (1/9) =
8/9
39 I think sry if I’m wrong
