Steam boat (b) = speed of 36.8km/h. In 1.75 hours out same port and going same direction departed speed boat (s). In 1.8 hours later distance between the speed boat (s) and steam boat (b) was 86.9km
Scenario A) the steam boat (b) stays ahead of the speed boat (s)
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Start by first finding the total distance (d) that the steam boat (b) traveled. That would be 1.75+1.8 = 3.55 hrs
distance (d) = rate (r) × time (t)
d(s) = rt = (36.8km/h)(3.55h) = 130.64 km
Secondly, let's subtract from d the distance between b and speed boat (s):
d(s) = 130.64 - 86.9km = 43.74 km
Thirdly, since s traveled 43.74 km and left 1.8 hrs ago, let's set-up the rate of b [r(b)] equal to that distance [d(s)] divided by the time 1.8 hrs.
**Since d = rt, r = d/t
r(s) = d(s)/t = 43.74km/1.8h = 24.3km/h
Scenario B) the speed boat (s) moves ahead of the steam boat (b), this is more likely!!
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b moves before s starts for 1.75 hrs, going 36.8km/h, that distance ahead + distance it travels after the next 1.8 hrs = 130.64 km
Now s starts and travels d(s) km at r(s) km/h
If s speeds past b in 1.8 hrs, and is AHEAD by the given distance of 86.9km, then total distance of s [d(s)] = the 130.64 b traveled PLUS the 86.9 it is now ahead
d(s) = 130.64+86.9 = 217.54 km
s still only traveled that in 1.8 hrs, so the speed/rate of s is:
r(s) = d(s)/t = 217.54km/1.8h = 120.86km/h
** I think that makes more sense, that a speed boat would move MUCH faster than a steam boat, if 120.9... than over 3 times faster!!
Answer:
<em>Option B</em>
Step-by-step explanation:
We can approach this problem through the formula for distance between points, but I can think of a more easier approach. This line forms a triangle with the x and y axis, a right triangle with the legs being 2 and 1 units. The line with which we must find the distance of acts as the hypotenuse of this triangle, so let us apply Pythagorean Theorem to solve for the length of the line;
<em>Solution; Option B</em>
Answer:
40w + 16p ≤ 2000
Step-by-step explanation:
let 'w' = jugs of water
let 'p' = cases of paper
the area of shading will include negative values which you can ignore because those values do not apply to this problem
Answer:
this is simply clever goggle lens
Step-by-step explanation:
you can do itttttttttttttttttttttttt
you can use long division to do this:-
a + 3 ) a^2 + 2a + 3
= a - 1 remainder 6 or you can write it as a - 1 + 6 / (a + 3)
