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andreyandreev [35.5K]
3 years ago
14

PLEASE HELP MEEE. <3

Mathematics
1 answer:
Alecsey [184]3 years ago
4 0
It’s D!!! Hope this helped;)
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Use the Quadratic formula to find all real zeros of the 2nd degree polynomial
schepotkina [342]

Answer:

  x ∈ {-5, -1}

Step-by-step explanation:

Here's the solution using the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-24\pm\sqrt{24^2-4\cdot 4\cdot 20}}{2\cdot 4}\\\\=\dfrac{-24\pm\sqrt{576-320}}{8}=\dfrac{-24\pm\sqrt{256}}{8}\\\\=\dfrac{-24\pm 16}{8}=-3\pm 2=\{-5,-1\}

The real zeros are -5 and -1.

_____

There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.

Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.

4 0
3 years ago
Pleasee i need help very bad
Anon25 [30]

Angles UST and TSU are equivalent.

The answer is TSU

3 0
3 years ago
What is -12 divided by 2/3? A. –36 B. –24 C. –18 D. –8
vazorg [7]

What is -12 divided by 2/3?


your answer is -18

5 0
3 years ago
3) For what price is 15 percent off the same as $75 off?
Kryger [21]

\text{In this question, you would need to find the right value that 15\% is \$75}\\\\\text{You can do this by multiplying each number by 0.15}:\\\\200*0.15=30\\\\300*0.15=45\\\\350*0.15= 52.5\\\\500*0.15=75\\\\\text{You would see that 15\% of 500 is \$75}\\\\\boxed{\$500}

3 0
3 years ago
Read 2 more answers
Determine the zeros of the function f(x) = 3x^2 -7x+1
IceJOKER [234]
I will use the quadratic formula.

\text{The zeros of function:}\ f(x)=0\\\\f(x)=3x^2-7\\\\f(x)=0\to3x^2-7x+1=0\\\\a=3;\ b=-7;\ c=1\\\\b^2-4ac=(-7)^2-4\cdot3\cdot1=49-12=37\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-(-7)-\sqrt{37}}{2\cdot3}=\dfrac{7-\sqrt{37}}{6}\\\\x_2=\dfrac{-(-7)+\sqrt{37}}{2\cdot3}=\dfrac{7+\sqrt{37}}{6}

6 0
3 years ago
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