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Arada [10]
3 years ago
15

Marcus is making a square pyramid out of cart board. He drew a diagram of a square pyramid as shown below. Based on Marcus’ diag

ram, how many square inches of cardboard
make up this square pyramid?

Mathematics
2 answers:
Andrew [12]3 years ago
4 0
7 inch lol i need points
Mandarinka [93]3 years ago
4 0

Answer:

24 in2 of cardboard

Step-by-step explanation:

I took the k12 test :)

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250cm3 of fresh water of density 1000kgm-3 is mixed with 100cm3 of sea water of density 1030kgm-3. Calculate the density of the
natka813 [3]

Answer:

m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg

And we can do a similar procedure for the sea water:

m_{sea}= \rho_{sea} V_{sea}

And after convert the volume to m^3 we got:

m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg

And then the density for the mixture would be given by:

\rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}

And replacing we got:

\rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}

Step-by-step explanation:

For this case we can begin calculating the mass for each type of water:

m_{fresh}= \rho_{fresh} V_{fresh}

And after convert the volume to m^3 we got:

m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg

And we can do a similar procedure for the sea water:

m_{sea}= \rho_{sea} V_{sea}

And after convert the volume to m^3 we got:

m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg

And then the density for the mixture would be given by:

\rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}

And replacing we got:

\rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}

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3 years ago
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