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3 years ago

5

Shania is making a scale diagram of the badminton court at the community center. She uses a scale of 1 centimeter to 0.5 meter t

o draw the scale diagram. If the scale length of the badminton court is 26.8 centimeters and the scale width is 12.2 centimeters, what is the actual area of the court?

1 answer:

kaheart [24]3 years ago

8 0

Answer: 13.4 meters by 6.1 meters

Step-by-step explanation: Applying the scale to the given measurements gives us: 13.4 meters long and 6.1 meters wide

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Why do many animals in grasslands stay together in herds?

mixas84 [53]

Answer:

plz put one qusetion a time plz so i can put it down better

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

7. A person has $10,100 to invest in two different stock. Stock ABC costs $32 per share and pays dividends of $1.20 per share. S

Vesna [10]

Answer:

invested in ABC = $3200

Step-by-step explanation:

given data

total invest = $10,100

Stock ABC costs = $32 per share

dividends = $1.20 per share

Stock XYZ costs = $23 per share

dividends = $1.40 per share

earn a total dividends = $540

solution

we can say total money invest express as

total money invested = 32 × P + 23 × Q

here person buys stocks of ABC is P and buys stocks of stocks of XYZ is Q

$10,100 = 32 × P + 23 × Q

we can also write this as by multiply 3 both side

$30,300 = 96 × P + 69 × Q ......................1

and total dividends will be

total dividends = 1.2 × P +1.4 × Q

$540 = 1.2 × P +1.4 × Q

we can also write this as by multiply 80 both side

$43200 = 96 × P + 112 × Q ....................2

so from equation 1 and 2 , subtracting 1 from 2

we get

Q = 300

and P = 100

so that we invest 100 × 32

invested in ABC = $3200

6 0

3 years ago

a student answers 75% of the questions on a math exam correctly. if he answers 30 questions correctly. how many questions are on

Komok [63]

There is 40 questions on the exam

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2 years ago

Mariah Jacobsen is the marketing manager at ABC Electronics, a major consumer electronics supplier in the northwest. Over the la

o-na [289]

Answer:

0.6568 = 65.68% probability that she would be correct.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

45000, 45500, 44500, 46000 and 44000 units. This rate of sales is considered average for the product over the last twenty years or so.

This means that:

$\mu = \frac{45000 + 45500 + 44500 + 46000 + 44000}{5} = 45000$

Standard deviation of 1500 units.

This means that $\sigma = 1500$

What is the likelihood that she would be correct if she predicts sales between 43000 and 46000?

This is the pvalue of Z when X = 46000 subtracted by the pvalue of Z when X = 43000. So

X = 46000

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{46000 - 45000}{1500}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486

X = 43000

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{43000 - 45000}{1500}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918

0.7486 - 0.0918 = 0.6568

0.6568 = 65.68% probability that she would be correct.

5 0

3 years ago

the straight line L, has equation y=3x-4 The straight line 1, in perpendicular to L, and passes through the point (9.5) Find an

kari74 [83]

Given:

The equation of given line is

$y=3x-4$

A line is perpendicular to the given line and passes through the point (9,5).

To find:

The equation of the perpendicular line.

Solution:

We have,

$y=3x-4$

On comparing this equation with slope intercept form $y=mx+b$ , we get

$m=3$

It means, the slope of the given line is 3.

The product of slopes of two perpendicular lines is -1.

$m\times m_1=-1$

$3\times m_1=-1$

$m_1=-\dfrac{1}{3}$

Point slope form of a line is

$y-y_1=m(x-x_1)$

Where, m is the slope.

The slope of perpendicular line is $-\dfrac{1}{3}$ and it passes through the point (9,5). So the equation of the line is

$y-5=-\dfrac{1}{3}(x-9)$

$y-5=-\dfrac{1}{3}(x)-\dfrac{1}{3}(-9)$

$y-5=-\dfrac{1}{3}x+3$

Adding 5 on both sides, we get

$y-5+5=-\dfrac{1}{3}x+3+5$

$y=-\dfrac{1}{3}x+8$

Therefore, the equation of required line is $y=-\dfrac{1}{3}x+8$ .

5 0

2 years ago