Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
A - 7 = -13
Add 7
A = -6
10X - 8 = 9X + 8
Add 8
10X = 9X + 16
Subtract 9X
X = 16
In a right triangle, where a and b are the shorter sides, and c is the longer side a^2+b^2=c^2
Thus, plug in the values.
12^2+16^2=20^2
144+256=400
400=400.
Because the equation is true, 12, 16, and 20 can be a right triangle
<em>Hope it helps <3</em>
Answer:
40
Step-by-step explanation:
We have an original price p
We mark them up by 50%
p + p*50%
Changing to decimal form
p+.50p = 1.5p
The new price is 60 dollars
1.5p = 60
Divide each side by 1.5
1.5p/1.5 = 60/1.5
p =40
The original price is 40
Answer:
Step-by-step explanation:
x² = 19x + 12
⇔ x² - 19x - 12 = 0
Calculating the discriminant :
b² - 4ac = (-19)² - 4×1×(-12) = 409
The discriminant is positive ,then the equation has two solutions.
One pair of opposite sides both parallel and congruent implies a parallelogram.
