R example: 6 1/2 = 13/2 = 6.5
For the first example, six and a half is equal to thirteen halves, which
is then equal to six point five. To do this, the rule to turn a mix
number into a fraction is by multiplying the 2 with the 6 and then add
the answer to 1, which gives 13/2 (Remember to always give the same
denominator). Finally, thirteenth halves is equal to six point five
(because when you divide 13 by 2, you get 6 and one left over. To
continue dividing, add a 0 , and so 10 goes into 2 is five. so the
decimal is 6.5
It would be 7.45 since the -3.05 and the -9.5 together would equal -12.55 which subtracted from 20 would equal 7.45
Let's go through the steps of factoring that Venita should take.
1.) Find the greatest common factor (GCF). We only have two terms, so that makes it pretty easy.
32 = 1, 2, 4, 8, 16, 32
8 = 1, 2, 4, 8
The greatest common factor of 32 and 8 is 8. We can also factor out a <em>b</em> since that term appears in each part of the original expression. The GCF and variable should go on the outside of the parentheses.
8b( )
2.) Now let's figure out what should go in the middle of the parentheses. To do this, use the original expression and divide each term. This is written in the parentheses.
32ab ÷ 8b = 4a
8b ÷ 8b = 1
This would then result in the factored expression 8b(4a - 1). You can always check this by using the distributive property. Distribute 8b out to both expressions:
8b x 4a = 32ab
8b x 1 = 8b
32ab - 8b is the expression she started with, so your factored expression works!
Now that we went through the steps to solve the factored expression, let's check her answer. The only difference between Venita's and ours is that she has 0 as the second term while we have a 1. It seems that she had subtracted the GCF from the second term instead of dividing.
Answer:
C. 
Step-by-step explanation:
Given the two equations:
To find:
The correct option when value of y is substituted to 2nd equation using the 1st equation.
Solution:
First of all, let us learn about the substitution method.
Substitution method is the method to provide solutions to two variables when we have two equations and two variables.
In substitution method, we find the value of one variable in terms of the other variable and put this value in the other equation.
Now, the other equation becomes only single variable and then we solve for the variable's value.
Here, we have two equations and value of one varible is:
Let us put value of y in 2nd equation:
So, the correct answer is option C.
Two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.
Length = 140 m ; Width = 68 m
Circumference of a circle = 2 π r circumference of a cirlce = 2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52
length = 2 * 140 m = 280 m
perimeter of the oval = 213.52 m + 280 m = 493.52 m
