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Vitek1552 [10]
3 years ago
14

Determine the perimeter of each figure.

Mathematics
2 answers:
Step2247 [10]3 years ago
5 0
Number 1. 306mm

Number 2.6in
MrMuchimi3 years ago
5 0
1. 306mm
2. I cant find out number 2
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avanturin [10]

Answer:

5f

Step-by-step explanation:

6 0
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Sedaia [141]

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I need to see letter P first mate XD

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3 years ago
What is the surface area of the sides and closed rectangular end? ____ sq. ft.
Alenkasestr [34]
Without the roof panels, the surface area (except for the open panel) is 176.25 sq. ft.
With the roof panels, the surface area (except for the open panel) is 196.67 sq. ft. 

The area of the rectangular sections (the sides without gables) is given by 10*6 = 60 sq. ft.  There are two of these sides, for a total of 2*60 = 120 sq. ft.

The gables are triangles, which have an area formula of
A = 1/2bh

For the gables, this is 1/2(1.5)(7.5) = 5.625 sq. ft.  Since there are two of them, this makes 2*5.625 = 11.25 sq. ft.

The closed side under a gable has an area of 6*7.5 = 45 sq. ft.

The two roof panels have an area of (4 1/12)(2 1/2) each:
49/12(5/2) = 245/24

There are two of them, which makes 490/24 = 20.42 sq. ft.

Without the roof panels, we have 45+11.25+120 = 176.25 sq. ft.
With the roof panels, we have 45+11.25+120+20.42 = 196.67 sq. ft.
4 0
4 years ago
8989890+85769090790509709-590
stich3 [128]

Answer:

8.5769091e+16

Step-by-step explanation:

7 0
3 years ago
When completing the square on the equation c2 + 110 = 12, the resulting solution is:<br> It
Delvig [45]

Answer:

c=1 and c=-12

Step-by-step explanation:

The correct equation is:

c^2+11c=12

To solve by completing the square method.

Solution:

We have:

c^2+11c=12

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

c^2+2.\frac{11}{2}c=12  

c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12

(c+\frac{11}{2})^2-(\frac{11}{2})^2=12  [As  c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2]

Adding both sides by (\frac{11}{2})^2

(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2

(c+\frac{11}{2})^2=12+\frac{121}{4}  

Taking LCD to add fraction.

(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}

(c+\frac{11}{2})^2=\frac{169}{4}

Taking square root both sides.

\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}

c+\frac{11}{2}=\pm\frac{13}{2}

Subtracting both sides by \frac{11}{2} :

c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}

c=\pm\frac{13}{2}-\frac{11}{2}

So, we have:

c=\frac{13}{2}-\frac{11}{2} and c=-\frac{13}{2}-\frac{11}{2}

c=\frac{2}{2} and c=\frac{-24}{2}

c=1 and c=-12  (Answer)

6 0
4 years ago
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