Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
Answer:
3/2 OR 1 1/2
Step-by-step explanation:
Collect like terms, meaning combine both y's. You should have something like this afterwards.
6y = 9
Now that you have that divide the 6 on both sides so Y is by itself!
Your answer is now 3/2.
