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3 years ago

6

Me. Adams divides 223 markers equally among the 26 students in his class. He puts the extra markers in a box. What is the least

number of markers he puts in the box?

1 answer:

Soloha48 [4]3 years ago

6 0

He puts 15 markers in the box. Hope this helps.

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The area of a duck enclosure is 300 square feet, with 100 square feet occupied by a pond. Each duck in the enclosure needs more

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2 years ago

Someone please answer this for me

AnnZ [28]

Answer:

2d+4p

Step-by-step explanation:

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2 years ago

If you make 1170 points out of 1800 what grade would I have

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3 years ago

Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally

sasho [114]

Answer:

a) $P(X$

$P(z$

b) $P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)$

$P(z>1.47)=1-P(z$

c) $P(3$

$P(-0.882$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

$X \sim N(4.5,1.7)$

Where $\mu=4.5$ and $\sigma=1.7$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using excel or the normal standard table:

$P(z$

Part b

We are interested on this probability

$P(X>3.0)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)$

And we can find this probability using excel or the normal standard table:

$P(z>1.47)=1-P(z$

Part c

$P(3$

And we can find this probability using excel or the normal standard table liek this:

$P(-0.882$

3 0

3 years ago

Pls help me with this question

MrMuchimi

I rather not..............

5 0

3 years ago