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PIT_PIT [208]
3 years ago
13

Write (3x)^2 without exponents

Mathematics
2 answers:
denis-greek [22]3 years ago
5 0
(3x)² can be rewritten as (3x)(3x), which means you multiply them together. 3 ×× 3 = 9, x × x = x², so your simplified answer is 9x². I hope this helps!
Likurg_2 [28]3 years ago
4 0
You can write it without exponent
3x*3x or 9x*x
You might be interested in
Equations and inequalities
DerKrebs [107]
Inequalities and equations use similar steps to solve, but inequalities give a range of numbers that can represent the variable while an equation will give a direct answer.

Example:

4+5x=24

First you would subtract 4 or add the opposite of 4 from 24.

4+5x=24
+(-4) +(-4)
—————
5x=20

Then divide each side by 5 or multiply each side by the reciprocal of 5 to isolate the variable.

1/5*5x=20*1/5 (reciprocal)
X= 4

You would use the same steps in an inequality but end up with a different sign.
8 0
3 years ago
Read 2 more answers
What is the quotient of 35,423 ũ 15?
My name is Ann [436]
Divide 35423 by 15 and round the answer down to a whole number, then you get 2361. If you subtract 15*2361 from 35423 you get the remainder 8. So answer C is correct.
5 0
3 years ago
Plz Help NO LINKS NO LINKS
Ann [662]

Answer:

The second one is correct.

6 0
3 years ago
We are throwing darts on a disk-shaped board of radius 5. We assume that the proposition of the dart is a uniformly chosen point
Vlad1618 [11]

Answer:

the probability that we hit the bullseye at least 100 times is 0.0113

Step-by-step explanation:

Given the data in the question;

Binomial distribution

We find the probability of hitting the dart on the disk

⇒ Area of small disk / Area of bigger disk

⇒ πR₁² / πR₂²

given that; disk-shaped board of radius R² = 5, disk-shaped bullseye with radius R₁ = 1

so we substitute

⇒ π(1)² / π(5)² = π/π25 = 1/25 = 0.04

Since we have to hit the disk 2000 times, we represent the number of times the smaller disk ( BULLSEYE ) will be hit by X.

so

X ~ Bin( 2000, 0.04 )

n = 2000

p = 0.04

np = 2000 × 0.04 = 80

Using central limit theorem;

X ~ N( np, np( 1 - p ) )

we substitute

X ~ N( 80, 80( 1 - 0.04 ) )

X ~ N( 80, 80( 0.96 ) )

X ~ N( 80, 76.8 )

So, the probability that we hit the bullseye at least 100 times, P( X ≥ 100 ) will be;

we covert to standard normal variable

⇒ P( X ≥  \frac{100-80}{\sqrt{76.8} } )

⇒ P( X ≥ 2.28217 )

From standard normal distribution table

P( X ≥ 2.28217 ) = 0.0113

Therefore, the probability that we hit the bullseye at least 100 times is 0.0113

3 0
3 years ago
If the sum of 8th and 9th terms of
mojhsa [17]
The answer is anime and chicken nuggets
4 0
3 years ago
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