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skad [1K]
3 years ago
12

Solve the problem that’s given in the image

Mathematics
2 answers:
Vikentia [17]3 years ago
5 0
The answer should be 112
Aleksandr [31]3 years ago
3 0

Answer:

112 cupcakes were mocha

Step-by-step explanation:

44% of 200 is 88 then subtract 88 from 200. hope this helps

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which of the circle diagrams below represnts the statement "if it is a square, then it is a quadrilateral
san4es73 [151]

Answer:

Step-by-step explanation:

yes

6 0
3 years ago
10. Which expression is represented by the model below?<br> +<br> o
galben [10]

I remember doing this one and its c

5 0
3 years ago
What are the values of x and y?<br><br> (Explain please it will help a lot,thanks)
Kitty [74]
X = 80
y = 85

If you look at only the left triangle, you can see that x is part of one of the angles. The 3 interior angles of the triangle add up to 180 degrees, so subtracting the other two angles, you get x + 30 = 110, or x = 80.

The same method can be used for the other triangle to find y.
5 0
4 years ago
Suppose an auto racer won a 400 mile race with a time of ​1:41​:58. at one point the racer was 40 miles closer to the finish tha
enot [183]
400/2 = 200
200 + 20 = 220
200 - 20 = 180
Answer: He had gone 220 miles.

He was 180 miles from the finish and 220 from the start, so he was 40 miles closer to the finish than to the start.
7 0
3 years ago
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
4 years ago
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