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Salsk061 [2.6K]
4 years ago
9

Write an equation and solve:

Mathematics
1 answer:
11Alexandr11 [23.1K]4 years ago
4 0

Answer

Find out  how many  months will it take for Jeff to weigh the same as Darius .

To prove

As given

Jeff and Darius are trying to gain weight for the football team.

Jeff weighs 120 pounds and is gaining  ten pounds per month.

Darius weighs 150 pounds and is gaining 4 pounds per month.

m = represented the number of months will taken by the Jeff to weigh the same as Darius .

Than the equation become in the form

120 + 10m = 150 +4m

150 - 120 = 10m - 4m

30 = 6m

m = \frac{30}{6}

m = 5 months

Therefore in 5 months  will it take for Jeff to weigh the same as Darius.

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Answer:

x=20

Step-by-step explanation:

x=20 because (4x+3)=77 so you take out of parnetheses

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Answer:

a = 16

w = 125

x = 120

y = 55

Step-by-step explanation:

<u>FINDING 'a'</u>

31 = a + 46 / 2

62 = a + 46

16 = a

<u>FINDING 'w'</u>

* This section looks Non-Isosceles trapezoid so I will be following the rule according it

w + 55 = 180

w = 125

<u>FINDING 'y'</u>

y = 55

- Because of corresponding angles

<u>FINDING 'x'</u>

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3 years ago
59.952 nearest tenth
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Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to
erastova [34]

Answer:

(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = Fell short of expectations

<em>B</em> = Met expectations

<em>C</em> = Surpassed expectations

<em>N</em> = no response

<u>Given:</u>

P (N) = 0.04

P (A) = 0.26

P (B) = 0.65

(a)

Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:

P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05

Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b)

The response of all individuals are independent.

Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

P(B\cup C) = P(B)+P(C)-P(B\cap C)\\=P(B)+P(C)-P(B)\times P(C)\\= 0.65 + 0.05 - (0.65\times0.05)\\=0.6675\\\approx0.67

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

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4 years ago
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