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Aleks04 [339]
3 years ago
8

Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to

indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 4% of respondents did not provide a response, 26% said that their experience fell short of expectations, 65% of the respondents said that their experience met expectations (Clarkson Magazine, Summer, 2001). If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations? If we chose an alumnus at random, what is the probability that the alumnus would say their experience met or surpassed expectations?
Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer:

(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = Fell short of expectations

<em>B</em> = Met expectations

<em>C</em> = Surpassed expectations

<em>N</em> = no response

<u>Given:</u>

P (N) = 0.04

P (A) = 0.26

P (B) = 0.65

(a)

Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:

P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05

Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b)

The response of all individuals are independent.

Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

P(B\cup C) = P(B)+P(C)-P(B\cap C)\\=P(B)+P(C)-P(B)\times P(C)\\= 0.65 + 0.05 - (0.65\times0.05)\\=0.6675\\\approx0.67

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

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aivan3 [116]
> multiply the second equation by 2 and add it to the first equation.
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8x + 14y = 4
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8(4) + 14y = 4
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2 years ago
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Tod begins piano practice at 4:15 p.M. And ends at 5:50 p.M. How long does he practice
nikdorinn [45]

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Step-by-step explanation:

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3 years ago
Select the number line that shows the decimal for the following fraction.<br><br> sixth tenths
Komok [63]

Answer:

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Step-by-step explanation:

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Answer:

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2 years ago
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adelina 88 [10]

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