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3 years ago

5

there are 72 new houses being built in a neighborhood. Last month, 1/3 of them were sold. This month, 5/8 of the remaining house

s were sold. how many houses are left to be sold?

1 answer:

Nataly_w [17]3 years ago

7 0

Answer:

15 houses

Step-by-step explanation:

1/3 * 72 = 24

5/8 * 24 = 15

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Which expression correctly represents the product 12(8 + 5) after applying

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D becaucause you have to do 12x8 and then 12x5 and whatever 12x8 is you but the answer bring down the + and do 12x5

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4 years ago

Find your mass if a scale on Earth reads 650N when you stand on it.

anygoal [31]

Answer:

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4 years ago

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

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Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

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now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

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7 0

3 years ago

Read 2 more answers

Need help with this question please!!

Luba_88 [7]

Answer:

11.1

Step-by-step explanation:

Use the Pythagorean theorem to find the unknown side.

$a^{2} +b^{2} =c^{2} \\AB^{2} +BC^{2} =AC^{2} \\AB^{2} +19^{2} =22^{2} \\\\AB^{2}=22^{2}-19^{2\\AB=\sqrt{123} \\AB=11.1$

8 0

3 years ago

What is the volume of this triangular Pyramid photo attached

storchak [24]

To find the volume of a triangular pyramid, the formula is:

$V=\frac{1}{3}(Area\text{ }of\text{ }thebase)(height)$

So we start by finding the area of the base, which is in the shape of a right triangle in this case.

The area of a right triangle is equal to 1/2 x base x height.

$\begin{gathered} A=\frac{1}{2}bh \\ \\ A=\frac{1}{2}(5)(6) \\ \\ A=15\text{ square feet} \end{gathered}$

We use this area to find the volume.

$\begin{gathered} V=\frac{1}{3}Ah \\ \\ V=\frac{1}{3}(15)(6) \\ \\ V=30\text{ cubic feet} \end{gathered}$

The volume of the triangular pyramid is 30 cubic feet.

3 0

2 years ago