Plz help me I want to solve the two questions in the picture plz

Nastasia [14]

Answer: The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try!

Step-by-step explanation:

7 0

3 years ago

Find two numbers if their sum is 91 and the ratio is 6:7.

Oduvanchick [21]

6:7....added = 13

6/13(91) = 564/13 = 42
7/13(91) = 637/13 = 49

ur 2 numbers are : 42 and 49

4 0

3 years ago

Read 2 more answers

If Tom brushes his teeth 1/12 hour a day. how many minutes does Tom brush his teeth in 2 weeks? What units of time do you need t

lilavasa [31]

1/12 hour = 5 minutes, 2 weeks is 14 days, so 5*15 = the amount of time he brushes his teeth so you would need to change from hours to minutes

6 0

3 years ago

Copy and complet the table compare the values of 2^x-2 with the values of 2^x-2

Vladimir79 [104]

#2^(x-2)

For 2

2^(2-2)=2⁰=1

For 3

2^(3-2)=2

For 4

2^(4-2)=2²=4

For 5

2^{5-2}=2³=8

For 6

2^{6-2}=2⁴=16

#2^x-2

For 2

2²-2=2

For 3

2³-2=6

For 4

2⁴-2=14

For 5

2⁵-2=30

For 6

2⁶-2=62

3 0

2 years ago

Read 2 more answers

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

likoan [24]

Answer:

A) 3%

B) Product A

Step-by-step explanation:

Exponential Function

General form of an exponential function: $y=ab^x$

where:

a is the initial value (y-intercept)
b is the base (growth/decay factor) in decimal form
x is the independent variable
y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

Part A

Product A

Assuming the function for Product A is exponential:

$f(x) = 0.69(1.03)^x$

The base (b) is 1.03. As b > 1 then it is an increasing function.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, product A is increasing by 3% each year.

Part B

$\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100$

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

$\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%$

Check using different two consecutive values of f(t):

$\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%$

Therefore, as 3% > 1%, Product A recorded a greater percentage change in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

a = 10,100
b = 1.01
n = t - 1 (as the initial value is for t = 1 not t = 0)

$\implies f(t) = 10100(1.01)^{t-1}$

To check this, substitute the values of t for 1 through 4 into the found function:

$\implies f(1) = 10100(1.01)^{1-1}=10100$

$\implies f(2) = 10100(1.01)^{2-1}=10201$

$\implies f(3) = 10100(1.01)^{3-1}=10303.01$

$\implies f(4) = 10100(1.01)^{4-1}=10406.04$

As these values match the values in the given table, this confirms that the found function for Product B is correct and that Product B increases by 1% per year.

4 0

2 years ago