The function in vertex form is y= (x+1)^2+4.
Answer:
x²+y² = 64
Step-by-step explanation:
The standard form of writing the equation of a circle is expressed as;
(x-a)²+(y-b)² = r² where;
(a, b) is the centre of the circle
r is the radius of the circle
Given the diameter of the circle with endpoints (8,0) and (-8, 0)
d = √(x2-x1)²+(y2-y1)²
d = √(-8-8)²+(0-0)²
d = √(-16)²
d = √256
d = 16
radius r = 16/2
r = 8
The centre of the circle will be the midpoint of the coordinates
M = (8-8/2, 0+0/2)
M = (0/2, 0/2)
M = (0,0)
Hence the centre is at (0,0)
Get the required equation
Recall that (x-a)²+(y-b)² = r²
Substitute the centre and the radius
(x-0)²+(y-0)² = 8²
x²+y² = 64
This gives the required equation
Okay so I'm guessing that they are two different formulas the f(x)= 3x and the f(x)= -5x-2. If that's is true then you would just have to plug in -2 to the x's. So then it would be f(x)= 3(-2) which if you solve it would give you f(x)= -6 and for the second one it would be f(x)= -5(-2)-2 so then you would solve for it and get f(x)= 8.
The answer would be 5/7 because I'm just trying to get brainly points lol
Answer:
use 2 defined points.
Lets use: (-3,0) and (0,3)
The equation is written as y = mx+b, where m is the slope and is the y-intercept
Slope - change in y / change in x:
Slope = (3 -0) /(0- -3) = 3/3 = 1
b is the y-intercept which is the y value when x is o, which is one of the points (0,3) so b = 3
The equation becomes y = x +3
