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natka813 [3]
3 years ago
11

If the parent function f(x)= 3sq rootx is transformed to g(x) = 3sq rootx + 2 - 4 , which is the graph of g(x)?

Mathematics
1 answer:
katrin [286]3 years ago
5 0

Let's analyze the changes made to the parent function one by one:

STEP 1: Horizontal translation.

If we transform

\sqrt{x}\mapsto \sqrt{x+2}

We're performing a change in the form of

f(x)\mapsto f(x+k)

This kind of changes result in a horizontal translation, k units to the left if k is positive, k units to the right if k is negative. In this case, k=2, so the original graph is shifted 2 units to the left.

STEP 3: Vertical stretch.

If we transform

\sqrt{x+2}\mapsto 3\sqrt{x+2}

We're performing a change in the form of

f(x)\mapsto kf(x)

This kind of changes result in a vertical stretch with scale factor k. If k is negative, the function is also reflected across the x axis. In this case, k=3, so the original graph is stretched vertically, with scale factor 3.

STEP 3: Vertical translation.

If we transform

3\sqrt{x+2}\mapsto 3\sqrt{x+2}-4

We're performing a change in the form of

f(x)\mapsto f(x)+k

This kind of changes result in a vertical translation, k units down if k is positive, k units up if k is negative. In this case, k= -4, so the graph is shifted 4 units down.

All, in all, the original graph is shifted 2 units to the right, then it's stretched vertically with scale 3, and then it's shifted 4 units down. The order is important!

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For Exercises 6–9, determine the number of real solutions for each quadratic equation without solving.
valentina_108 [34]

Answer:

1) one real solution

2) no real solution

3) two real solutions

4) no real solution

Step-by-step explanation:

We have to determine the number of real solutions for each quadratic equation without solving.

ax^2 + bx +c=0\\D = b^2-4ac\\\text{If D is positive there are two real solutions}\\\text{Pif D is zero then there is one real solution}\\\text{if D is negative then there are no real solution.}

1)

p^2 + 7p + 33 = 8 - 3p\\p^2+10p+25=0\\D = 10^2 - 4(1)(25) = 0

Thus, the quadratic equation has one real solution.

2)

7x^2 + 2x + 5 = 0\\D = 2^2 - 4(7)(5) < 0

Thus, the quadratic equation has no real solution.

3)

2y^2 + 10y = y^2 + 4y - 3\\y^2+6y+3=0\\D = 6^2 - 4(1)(3) > 0

Thus, the quadratic equation has two real solutions.

4)

4z^2 + 9 = -4z\\4z^2 + 4z + 9 = 0\\D =4^2 - 4(4)(9) < 0

Thus, the quadratic equation has no real solution.

3 0
3 years ago
Y-125 = O A. -15 O B. -25 O c. -5 C. O D. 5 or -5​
timurjin [86]

Answer:

-5

Step-by-step explanation:

Cube root of -125 has to be -5

3 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!
Elena-2011 [213]

Answer:

Option B, none of these

Step-by-step explanation:

The graph makes a Square

Answer:  Option B, none of these

Graph Below:  

5 0
3 years ago
Read 2 more answers
Name one real-world objeslct that suggests points​
JulijaS [17]

Answer:

magnets

Step-by-step explanation:

counter

bottle cap

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6 0
4 years ago
Explain what is meant by the equation lim x → 8 f(x) = 9. If |x1 − 8| &lt; |x2 − 8|, then |f(x1) − 9| &lt; |f(x2) − 9|. The valu
loris [4]

Complete Question

1 Explain what is meant by the equation lim x → 8 f(x) = 9.

A If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|.

B The values of f(x) can be made as close to 8 as we like by taking x  sufficiently close to 9.

C  f(x) = 9 for all values of x.

D If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|.

E The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8.

2  Is it possible for this statement to be true and yet f(8) = 6? Explain.

A Yes, the graph could have a hole at (8, 9) and be defined such that f(8) =6.

B Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6.

C No, if f(8) = 6, then lim x→8 f(x) = 6.

D No, if lim x→8 f(x) = 9, then f(8) = 9.

Answer:

1

   The correct option is  D

2

    The correct option is   A

Step-by-step explanation:

Generally a a limit function  \lim_{n \to x }  f(x) = L

Tell us that as n tends toward x the values of  f(x) tends towards L hence for the first question E is the correct option

Now looking at the second question

  Yes it is possible for  lim x → 8 f(x) = 9.  to be true and  f(8) = 6 this is because the graph defined by this limit equation can have a hole the point

(8, 9) and created in such a way that f(8) = 6

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3 years ago
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