Answer:
A. width = x - 4.5
B. 111 = 2(x + (x -4.5))
Step-by-step explanation:
A. The width is 4.5 meters shorter than x, so is x -4.5.
__
B. The perimeter is twice the sum of length and width. It is 111 meters, so an equation for it could be ...
111 = 2(x + (x -4.5))
Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.
Answer:
8,541.023 and 154340
Step-by-step explanation:
Answer:
97
Step-by-step explanation:
For this equation we have to plug in, so z= 6 and w=7. the question is 8z+7w
so plug in 6 for z and 7 for w. 8(6)+7(7) so 8*6 is 48 and 7*7= 49. 48+49= 97
hope this helps :)
Answer:
maximum 4 Mimimum I'm 0 or maximum 10 minimum 0
