The volume is the product of the side lengths which is 1*6*11= 66 mm^3. The surface area is twice the sum of all the possible products of the side lengths, or 2lw+2wh+2hl which is 2(6*11+6*1+11*1) = 166 mm^2 if my mental math is decent.
Answer:
<h3>The answer is 4.9cm</h3>
Step-by-step explanation:
To find the perpendicular distance between them that's the height we use the formula
![Area \: \: of \: \: a \: \: trapezium = \frac{1}{2} (a + b) \times h](https://tex.z-dn.net/?f=Area%20%5C%3A%20%20%5C%3A%20of%20%5C%3A%20%20%5C%3A%20a%20%5C%3A%20%20%5C%3A%20trapezium%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%28a%20%2B%20b%29%20%5Ctimes%20h)
where
a and b are the parallel sides of the trapezium
h is the perpendicular distance
From the question
Area = 31.5cm²
a = 7.5 cm
b = 5.3 cm
Substituting the values into the above formula we have
![31 .5 = \frac{1}{2} (7.5 + 5.3) \times h](https://tex.z-dn.net/?f=31%20.5%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%287.5%20%2B%205.3%29%20%5Ctimes%20h)
![31.5 = \frac{1}{2} \times 12.8h](https://tex.z-dn.net/?f=31.5%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%2012.8h)
![31.5 = 6.4h](https://tex.z-dn.net/?f=31.5%20%3D%206.4h)
Divide both sides by 6.4
![h = \frac{31.5}{6.4}](https://tex.z-dn.net/?f=h%20%3D%20%20%5Cfrac%7B31.5%7D%7B6.4%7D%20)
h = 4.921875
We have the final answer
<h3>h = 4.9cm</h3>
Hope this helps you
Hmmmm I take it you meant those rationals to be exponents, so hmmm asumming that,
Answer: 0.05
Step-by-step explanation:
- Sampling error is the error occurs by considering sample for study instead of entire population.
Given : The proportion of items in a population that possess a specific attribute is known to be 0.45.
Sample size : n= 100
Sample proportion of items in a population that possess a specific attribute : ![\hat{p}=0.48](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D0.48)
Now, the formula to find the sampling error :
![\text{Sampling error} =\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Ctext%7BSampling%20error%7D%20%3D%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
![\text{Sampling error} =\sqrt{\dfrac{0.48(1-0.48)}{100}}](https://tex.z-dn.net/?f=%5Ctext%7BSampling%20error%7D%20%3D%5Csqrt%7B%5Cdfrac%7B0.48%281-0.48%29%7D%7B100%7D%7D)
![=\sqrt{\dfrac{0.48(0.52)}{100}}\\\\=\sqrt{0.002496}\approx0.05](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%5Cdfrac%7B0.48%280.52%29%7D%7B100%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0.002496%7D%5Capprox0.05)
Hence, the sampling error =0.05