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aleksandrvk [35]
4 years ago
12

(x, 7) and (11, 8); m = -1/5 Plz help

Mathematics
1 answer:
Kay [80]4 years ago
7 0

Answer:

This tells us that the line with slope -1/5 passes through the two points (16, 7) and (11, 8).  The previously unknown x-coordinate is 16.

Step-by-step explanation:

A line with slope m = -1/5 passes through the points (x, 7) and (11, 8).  Find the value of x.

The slope of the line through these two points is found from the slope formula and is:

        8 - 7

m = ----------- and the value of m is given as -1/5.  Therefore,

         11 - x

           1

m = ----------- =  -1/5

         11 - x

Cross-multiplying, we get (1)(5) = -(11 - x), or 5 = -11 + x.  Then x = 16

This tells us that the line with slope -1/5 passes through the two points (16, 7) and (11, 8).  The previously unknown x-coordinate is 16.

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6 0
3 years ago
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P, Q, V, and K are collinear with V between K and P, and Q between V and K. If VP = 14x + 4, PK = x + 630, VQ = 17x + 6, and KQ
Ierofanga [76]

It's given in the question,

P, Q, V and K are collinear.

VP = 14x + 4

PK = x + 630

VQ = 17x + 6

KQ = 11x + 5

By segment addition postulate,

KQ + VQ + VP = KP

Substitute the values in the expression,

(11x + 5) + (17x + 6) + (14x + 4) = x + 630

(11x + 17x + 14x) + (5 + 6 + 4) = x + 630

42x + 15 = x + 630

42x - x = 630 - 15

41x = 615

x = \frac{615}{41}

x = 15

Therefore, value of VP = (14x + 4)

                                      = 14(15) + 4

                                      = 214 units

Learn more,

brainly.com/question/628239

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3 years ago
HELPPP PLS ITS FOR MY TEST
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I believe that it is corresponding angle.
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Hope this helped :)
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