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4 years ago

each month for 7 months, samuel mows 3 lawns. how many mire lawns does he need to mow before he has mowed 29 lawns

1 answer:

7 0

Hello! I would love to help!

Okay, let's think. We know that for 7 months, he mowed 3 lawns. Basically, you can picture 7 groups with 3 lawns in each.

Essentially, what the first part of the problem is asking is: What is 3 times 7?

We can do that!

3*7=21

So we now know that he has already mowed 21 lawns. But, we also know that in all, Samuel has to mow 29 lawns. So how do we take away the 21 lawns from the 29 he has to do in all?

Tha answer: Let's subtract!

29-21=8

So, your answer is 8 more lawns!

Hope this helped! Comment if you have any questions!

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If i can see it right, it would be A because it starts at 30, then rises as the number of rooms increases.

4 0

3 years ago

What is (5.6*10^6)-340,000 <br><br>

KiRa [710]

Answer:

5260000

Step-by-step explanation:

3 0

3 years ago

Measurements of the sodium content in samples of two brands of chocolate bar yield the following results (in grams):

Tpy6a [65]

Answer:

98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .

Step-by-step explanation:

We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;

Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95

Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60

Also, $\mu_X$ represent the population mean for Brand B and let $\mu_Y$ represent the population mean for Brand A.

Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;

P.Q. = $\frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t_n__1+n_2-2$

where, $Xbar$ = Sample mean for Brand B data = 36.9

$Ybar$ = Sample mean for Brand A data = 32.9

$n_1$ = Sample size for Brand B data = 13

$n_2$ = Sample size for Brand A data = 9

$s_p = \sqrt{\frac{(n_1-1)s_X^{2}+(n_2-1)s_Y^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(13-1)*10.4+(9-1)*7.1 }{13+9-2} }$ = 3.013

Here, $s^{2}_X$ and $s^{2} _Y$ are sample variance of Brand B and Brand A data respectively.

So, 98% confidence interval for the difference μX−μY is given by;

P(-2.528 < $t_2_0$ < 2.528) = 0.98

P(-2.528 < $\frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 2.528) = 0.98

P(-2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ < $(Xbar -Ybar) -(\mu_X-\mu_Y)$ < 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ) = 0.98

P( (Xbar - Ybar) - 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ < $(\mu_X-\mu_Y)$ < (Xbar - Ybar) + 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ) = 0.98

98% Confidence interval for μX−μY =

[ (Xbar - Ybar) - 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ , (Xbar - Ybar) + 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ]

[ $(36.9 - 32.9)-2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9}$ , $(36.9 - 32.9)+2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9}$ ]

[ 0.697 , 7.303 ]

Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .

4 0

3 years ago

2 Richard and Jason each begin filling pools at the same time.

alina1380 [7]

The quantity of the liquid in Richard's tank after 20 minutes will be 120 gallons and in Jason's tank will be 240 gallons.

<h3>What are gallons?</h3>

A gallon is a British unit which is used for the measurement of liquids that is equal to eight pints. In Britain, it is equal to about 4.546 litres. In America, it is equal to about 3.785 litres.

It is given in the question that:-

Richard fills his pool at a rate of 6 gallons per minute.

Jason's pool already contains 200 gallons, and he fills it at a rate of 2 gallons per minute.

After 20 minutes the amount of liquid in the tank will be:-

For Richard = 6 gallons per minute. x 20 minutes= 120 gallons

For Jason= 2 gallons per minute x 20 =40 gallons

Jason has 200 gallons already in the tank

So it will become = 200+24=240 gallons.

Hence quantity of the liquid in Richard's tank after 20 minutes will be 120 gallons and in Jason's tank will be 240 gallons.

To know more about Gallons follow

brainly.com/question/16691874

#SPJ1

7 0

2 years ago

Multiply the binomials: (w-9) • (w-4)

Novay_Z [31]

Answer:

w² - 13w + 36

Step-by-step explanation:

Given

(w - 9)(w - 4)

Each term in the second factor is multiplied by each term in the first factor, that is

w(w - 4) - 9(w - 4) ← distribute both parenthesis

= w² - 4w - 9w + 36 ← collect like terms

= w² - 13w + 36

3 0

3 years ago