15 3/4 divided by 1 3/4

Tamara and Jason work at a widget factory. Tamara arrived at work before Jason and began making widgets. Tamara had already made

Elina [12.6K]

Answer:

To solve this problem we can construct an linear algebraic expression for each person, principally denoted as:

where

y :is our dependent variable (which is a function of )

x :is our independent variable

a :is the slope

c :is the y-intercept constant value (if any present)

Part A: Write a system of equations to represent the situation. Let x = hours and y = widgets.

Tamara

Has already made 20 widgets and produces at a rate of 8 widgets per hour thus here c=20 and a=8 , so Tamara's equation reads: yT=8x+20

Jason

Has not produced any widgets yet and produces at a rate of 12 widgets per hour thus here c=0 and a=12 , so Jason's equation reads:yj=12x

So the system of equations will be

yT=8x+20

yj=12x

Part B: How much time does it take for Tamara and Jason to produce the same number of widgets?

Since we want to find the amount of time (i.e. the value of x ) it takes for both of them to produce the same number of widgets we can just equate the two equations ans solve for x as follow:

yT=yj

8x+20=12x

8x-12x=-20

-4x=-20

x=5

So it takes them 5 hours to produce the same amount of widgets

Part C: How many widgets will Tamara and Jason have produced?

Now we can simply plug in the value of x=5 in any of the two equations (i.e. either for Tamara or Jason) to find the number of widgets produced.

yT=8(5)+20=40+20=60

So in a time-space of 5 hours Each will have produced 60 widgets and in total will be 60+60 = 120 widgets.

Step-by-step explanation:

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8 0

3 years ago

Please help! I dont understand! Thank you

Digiron [165]

QUESTION A

The given inequality is

$x-1\:>\:5$

Add 1 to both sides of the inequality to obtain;

$x\:>\:5+1$

$x\:>\:6$

Answer: 2. $x\:>\:6$ , open dot at 6 and shaded to the right.(A)

QUESTION B.

The given inequality is $2x \le 6$ .

Divide both sides by 2;

$x \le \frac{6}{2}$ .

$x \le 3$ .

Answer: 5. $x \le 3$ , closed dot at 3 and shaded to the left(B).

QUESTION C

The given inequality is $x-7\:>\:-4$

Add 7 to both sides to get;

$x\:>\:-4+7$

$\Rightarrow x\:>\:3$

Answer: 7. $x\:>\:3$ , open dot at 3 and shaded to the right.(C)

QUESTION D

We want to solve;

$-2x \:$

Divide through by -2 and reverse the inequality sign;

$x \:>\:\frac{6}{-2}$

$x \:>\:-3$

Answer; 3. $x \:>\:-3$ Open dot at -3 and shaded to the right. (D)

QUESTION E

We have

$4\:$

Divide through by -4 and reverse the sign.

$\frac{4}{-4}\:>\:x$

$-1\:>\:x$

or

$x\:$

Answer: 6. $x\:$ open dot at -1, and shaded to the left(E)

QUESTION F

The given inequality is $-2x+3\:$

Add -3 to both sides to get;

$-2x\:$

Divide both sides of the inequality by -2 and reverse the sign;

$x\:>\:5$

Answer:9. $x\:>\:5$ , open dot at 5 and shaded to the right(F)

QUESTION G

The given inequality is

$5x+1\ge11$

$5x\ge11-1$

$5x\ge10$

Divide by 5

$x\ge2$

Answer ; 10. $x\ge2$ , closed dot at 2 and shaded to the right(G)

QUESTION H

We have $3(x+4)\:>\:8x-6$

Expand the bracket to get;

$3x+12\:>\:8x-6$

Group similar terms to get;

$3x-8x\:>\:-6-12$

Simplify

$-5x\:>\:-18$

Divide through by -5 and reverse the sign;

$x\:$

Answer: 1. $x\:$ Open dot at 18/5 and shaded to the left(H)

QUESTION I

We have $-3x+4\:$ .

$-3x+x\:$

$-2x\:$

Divide by -2 and reverse the sign;

$x\:>\:1$

Answer: 8. $x\:>\:1$ , open dot at 1 and shaded to the right(I)

J. The given inequality $-2(x-4)\:>\:5-(x+2)$

Expand the bracket to get;

$-2x+8\:>\:5-x-2$

Group like terms to get;

$-2x+x\:>\:5-2-8$

$-x\:>\:-5$

Divide by -1 and reverse the sign to get;

$x\:$

Answer; 4. $x\:$ , open dot at 5 and shaded to the left.(J)

6 0

4 years ago

14. fourteen is half of g

DerKrebs [107]

If 14 is half of g, then g must equal 28.

14*2=28

8 0

3 years ago

Read 2 more answers

Can someone please help me out with this I’ve been stuck on it

Sonja [21]

Answer:

-3

Step-by-step explanation:

-9+6

=6-9

=-3

6 0

4 years ago

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The passcode to a game must contain 2 letters and 3 digits. How many codes are available if the 2 letters must be different and

viva [34]

Answer:

6

Step-by-step explanation:

3,2,1

5 0

3 years ago