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Anni [7]
2 years ago
10

One day, 148 copies of the student

Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
6 0

Answer:

312 copies

Step-by-step explanation:

100 + 100 = 200

40 + 60 = 100

8 + 4 = 12

200 + 100 + 12 = 312 copies

mote1985 [20]2 years ago
6 0
The answer is 312 copies
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What is the solution to this equation?
tresset_1 [31]

Answer:

x = 9

Step-by-step explanation:

First, we want to isolate variable x on the left side of the equation. We can do this by adding 13 to both sides.

x - 13 + 13 = - 4 + 13

x = 9

8 0
3 years ago
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3- y3 is the simplified form of (x+y) (22 - xy + y )<br> True<br> Or <br> False
sasho [114]

Answer:true

Step-by-step explanation:

6 0
2 years ago
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If h(x) = (f o g)(x) and h(x) = sqrt(x+5), find g(x) if f(x) = sqrt(x+2)
agasfer [191]

Answer:

  • g(x) = x + 3

Step-by-step explanation:

<h3>Given</h3>
  • h(x) = (f ο g)(x)
  • h(x) = \sqrt{x+5}
  • f(x) = \sqrt{x+2}
<h3>To find</h3>
  • g(x)
<h3>Solution</h3>

<u>We know that:</u>

  • (f ο g)(x) = f(g(x))

<u>Substitute x with g(x) and solve for g(x):</u>

  • \sqrt{x+5} = \sqrt{g(x)+2}
  • x + 5 = g(x) + 2
  • x + 3 = g(x)
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7 0
3 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
Solve the inequality for x<br> -x+23&lt;2-2(x-8)
lesya [120]

Answer:

inequality form: x<-5

Step-by-step explanation:

3 0
2 years ago
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