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Aleks [24]
3 years ago
8

Two DHCP servers, Server1 and Server2, are running Windows Server 2016. As the administrator, you create a scope called Scope1.

Server1 is the primary DHCP server. Which of the following best describes the easiest way to assign 80% of the addresses to Server1 and 20% to Server2?
a. On Scope1, run the DHCP Split-Scope Configuration Wizard.b. Create a multicast scope.c. Create a DHCP policy.d. Create a superscope.
Computers and Technology
1 answer:
kumpel [21]3 years ago
5 0

Answer:

The answer is "Option a"

Explanation:

Split-scope is also an easy and simple approach to deliver DHCP consistency and workload management into your system. Server 2008 R2 provides a convenient divide-scope guide which removes several operational efforts but can only be to use if all databases run on R2, and wrong choices can be described as follows:

  • In option b, It uses the Ip address for multicast, that's why it is wrong.
  • In option c, It is wrong because it uses a windows interface, that works on policies.  
  • In option d, It is wrong because it is an administrative feature.

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1. Write programming code in C++ for school-based grading system. The program should accept the Subject and the number of studen
satela [25.4K]

In this program, I am using the school-based grading system and the program should accept the subject and the number of students.

Program approach:-

  • Using the necessary header file.
  • Using the standard I/O namespace function.
  • Define the main function.
  • Declare the variable.
  • Display enter obtain marks in 5 subjects.
  • Return the value.

Program:-

//header file

#include<iostream>

//using namespace

using namespace std;

//main method

int main()

{

//declare variable

  int j;

  float mark, sum=0, a;

//display enter obtain marks in 5 subjects

  cout<<"Enter Marks obtained in 5 Subjects: ";

  for(j=0; j<5; j++)

  {

      cin>>mark;

      sum = sum+mark;

  }

  a = sum/5;

//display grade

  cout<<"\nGrade = ";

  if(a>=91 && a<=100)

//display a1

      cout<<"a1";

  else if(a>=81 && a<91)

//display a2

      cout<<"a2";

  else if(a>=71 && a<81)

      cout<<"b1";

  else if(a>=61 && a<71)

      cout<<"b2";

  else if(a>=51 && a<61)

//display c1

      cout<<"c1";

  else if(a>=41 && a<51)

//display c2

      cout<<"c2";

  else if(a>=33 && a<41)

//display d

      cout<<"d";

  else if(a>=21 && a<33)

//display e1

      cout<<"e1";

  else if(a>=0 && a<21)

//display e2

      cout<<"e2";

  else

//display invalid

      cout<<"Invalid!";

  cout<<endl;

//return the value

  return 0;

}

Learn more grading system

brainly.com/question/24298916

7 0
2 years ago
No spamming or links
Hitman42 [59]
I think the answer is true,
8 0
2 years ago
Read 2 more answers
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