Answer:
A rectangular lot is 100 meters wide and 150 meters long.Give the length and width of another rectangular lot that has the same perimeter but a smaller area.
The rectangular lot is having length of 170 meters and width of 80 meters.
Step-by-step explanation:
Given:
A rectangle.
Length of the rectangle = 150 meters
Width of the rectangle =100 meters
So perimeter of this rectangle = 2 (width+ length)
And area of this rectangle =(width)(length)
- Perimeter =
=
= meters.
- Area =
=
= square meters.
Now we have to find an another rectangular lot which has the same perimeter but different area.
Note: Subtract 20 m from the width and add 20m length into the longer side. (We can try with another multiple of 10).
So,
The new width = 100-20 = 80 meters.
And the new length =150+20 = 170 meters.
Lets check the perimeter and its area.
The perimeter must be equivalent to 500 meters and its area be less than 30000 sq-meters.
- Perimeter =
=
= meters.
- Area =
=
= square meters.
Hence the rectangular lot with length 170 m and with 80 m proves to have same perimeter and smaller area.
Answer: (B is the answer.
Step-by-step explanation: The graph I attached corresponds with B.
Cross -3 by -2.
Answer:
I believe the correct answer is point C
Step-by-step explanation: Hope this helped!
Answer:
=406 piglets in the warehouse
Step-by-step explanation:
578-126=452
452-46=406
Answer:
-6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
3x + 5x - 6
<u>Step 2: Simplify</u>
- [Addition] Combine like terms: 8x - 6
<u>Step 3: Identify</u>
8x -> variable
-6 -> constant