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3 years ago

What is the value of the 4 in 6.54

Mathematics

2 answers:

Nuetrik [128]3 years ago

7 0

The 4 in that number is in the hundredths section. It means the 4 represents four hundredths

Marysya12 [62]3 years ago

5 0

The value of the 4 in 6.54 is four hundreths.

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What is 3760 over 7916 reduced?

umka2103 [35]

3760/7916

reducing this fraction is simplifying it, so that means

3760/7916=940/1979

7 0

4 years ago

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A bag contains 4 white, 3 blue, and 6 red marbles. A marble is drawn from the bag, replaced, and another marble is drawn. Find t

PilotLPTM [1.2K]

First find the probability of each color being drawn.

We need to find the total number of marbles first.

4 + 3 + 6 = 13

So everything will be over 13.

Probability of a white marble being drawn --> $\frac{4}{13}$

Probability of a blue marble being drawn --> $\frac{3}{13}$

Probability of a red marble being drawn --> $\frac{6}{13}$

Now to find the probabilities of more than one being drawn, we can multiply.

Part a :

$\frac{6}{13}*\frac{6}{13}=\frac{36}{169}$

Part b :

$\frac{3}{13}*\frac{3}{13}=\frac{9}{169}$

Part c :

$\frac{6}{13}*\frac{3}{13}=\frac{18}{169}$

Part d :

$\frac{7}{13}*\frac{7}{13}=\frac{49}{169}$

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3 years ago

Find the equation in slope-intercept form that describes each line.

Andrews [41]

Answer: The answer is c- y=-2x+4

Explanation:

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3 years ago

Give an example of an odd function and explain algebraically why it is odd. (3 points)

klio [65]

Answer:

See below

Step-by-step explanation:

In an odd function f(-x) will equal -f(x).

An example is f(x) = x^3:-

f(-x) = (-x)^3 and -f(x) = -x^3:-

(-x)^3 = -x * -x * -x = -x^3.

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3 years ago

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If x = 4 tan(θ), find sec(θ) in terms of x

prisoha [69]

Answer:

$\sec \theta = \pm \frac{ \sqrt{ {x}^{2} + 16} }{4}$

Step-by-step explanation:

$\because \: x = 4 \tan \theta \\ \therefore\frac{x}{4} = \tan \theta....(1) \\ \\ \because \: { \sec}^{2} \theta = 1 + { \tan}^{2} \theta \\ \therefore \: \sec \theta = \pm\sqrt{1 + { \tan}^{2} \theta } \\ \therefore \: \sec \theta = \pm\sqrt{1 + { \bigg( \frac{x}{4} \bigg)}^{2} } \\ \therefore \: \sec \theta = \pm\sqrt{1 + { \frac{x^{2}}{16} } } \\ \therefore \: \sec \theta = \pm\sqrt{{ \frac{16 + x^{2}}{16} } } \\ \therefore \: \sec \theta = \pm \frac{ \sqrt{ {x}^{2} + 16} }{4}$

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3 years ago