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Nesterboy [21]
4 years ago
5

We have two fractions, \dfrac{1}{6} 6 1 ​ start fraction, 1, divided by, 6, end fraction and \dfrac{3}{8} 8 3 ​ start fraction,

3, divided by, 8, end fraction, and we want to rewrite them so that they have a common denominator (and whole number numerators). What numbers could we use for the denominator? Choose 2 answers: Choose 2 answers: (Choice A) A 121212 (Choice B) B 242424 (Choice C) C 161616 (Choice D) D 4848
Mathematics
1 answer:
andrew-mc [135]4 years ago
7 0

Answer:

<em>B) 24</em>

<em>D) 48</em>

<em></em>

Step-by-step explanation:

Given:

Two fractions

\dfrac{1}6 \\and\\\dfrac{3}8

To find:

Number that can be chosen as Common denominator such that numerator is also a whole number ?

Solution:

Common denominator for two fractions \frac{p}{q} and \frac{r}{s} is chosen as LCM or multiple of LCM of (q, s).

OR

Common denominator for two fractions is chosen as the Least Common Multiple or multiple of LCM of denominators of the two fractions.

The denominators of the given fractions are 6 and 8.

Let us factorize and try to find the LCM of 6 and 8.

6 = \underline2 \times 3\\8 = \underline2 \times 2\times 2

Common part of the denominators (as underlined) will be taken only once.

So, LCM = 2 \times 3 \times 2 \times 2 =24

Multiples of LCM, 24 = 48

So, the correct answers are:

<em>B) 24 </em>and

<em>D) 48</em>

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Step-by-step explanation:

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When using the rational root theorem, which of the following is a possible root of the polynomial function below f(x)=x^3-5x^2-1
uranmaximum [27]

Answer:

\Large \boxed{\sf \ \ 7 \ \ }

Step-by-step explanation:

Hello, please consider the following.

The polynomial function is

x^3-5x^2-12x+14

The rational root theorem states that each rational solution

   x=\dfrac{p}{q}    

, written in irreducible fraction, satisfies the two following:

   p is a factor of the constant term

   q is a factor of the leading coefficient

In this example, the constant term is 14 and the leading coefficient is 1. It means that p is a factor of 14 and q a factor of 1.

Let's proceed with the prime factorisation of 14:

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Finally, the possible rational roots of this expression are :

   1

   2

   7

   14

and we need to test for negative ones too

   -1

   -2

   -7

   -14

From your list, the correct answer is 7.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
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