How do you write 519 3/10 in decimal

4(x+9)=8x-7<br> Solve for x

valentina_108 [34]

Answer:

x = 10.75

Step-by-step explanation:

4(x+9)=8x-7

Step 1: Distribute the 4 to the x and 9

4 * x = 4x

4 * 9 = 36

We now have 4x + 36 = 8x - 7

Step 2: add 7 to both sides

36 + 7 = 43

-7 + 7 cancels out

We now have 4x + 43 = 8x

Step 3 subtract 4x from both sides

4x - 4x cancels out

8x - 4x = 4x

We now have 4x = 43

step 4 divide both sides by 4

4x / 4 ( the 4s cancel out and we're left with x )

43/4 = 10.75

We're left with x = 10.75

3 0

2 years ago

How do you do this promblem?

Sladkaya [172]

I don’t know but I need to answer a question so this is my answer

7 0

3 years ago

Read 2 more answers

Find f · dr c for the given f and

ruslelena [56]

Parameterize the path $\mathcal C$ by

$\mathbf r(t)=x(t)\,\mathbf i+y(t)\,\mathbf j$

with

$x(t)=3\cos t$
$y(t)=3\sin t$

and $0\le t\le\pi$ . Then

$\displaystyle\int_{\mathcal C}\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=\pi}\mathbf f(x(t),y(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt$
$=\displaystyle\int_0^\pi(9\cos^2t\,\mathbf i+9\sin^2t\,\mathbf j)\cdot(-3\sin t\,\mathbf i+3\cos t\,\mathbf j)\,\mathrm dt$
$=27\displaystyle\int_0^\pi(\cos t\sin^2t-\sin t\cos^2t)\,\mathrm dt=-18$

5 0

3 years ago

The area of a rectangle is 24 square centimeters. The length (X), in centimeters of the rectangle is given by the equation x2 +

Allisa [31]

The length of the rectangle is 3 cm

<h3>Applications of Quadratic equations</h3>

From the question, we are to determine the value of the length of the rectangle

To find the length of the rectangle, we will determine the value of x in the given equation

The given equation is

$x^{2} + 5x =24$