1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kogti [31]
3 years ago
15

Which statement is true?

Mathematics
1 answer:
evablogger [386]3 years ago
7 0
A) |-12| = -12 is false. There is no solution.
B) |-4| < 3 is false. There is no solution.
C) |-5| > 0 is 0 < 5. It is true. 
D) |-8| < |8| is false. There is no solution
You might be interested in
Evaluate each expression for the given value(s) of the variable(s). 2b + 9 when b = 3
Phoenix [80]

Answer:

15

Step-by-step explanation:

substitute the value of the variable into the equation and simply

6 0
3 years ago
you were planning to use a ceramic tile design in your new bathroom. The towels are blue and white equilateral triangle of you d
Sonja [21]
I found the image that should have accompanied this problem.

Given:
equilateral triangle with sides that measures 7cm.
hexagonal shape meaning 6 sides or 6 equilateral triangles used.

Area of an equilateral triangle = √3/4 * a²
A = √3 /4 * (7cm)²
A = 1.73/4 * 49cm²
A = 21.20 cm²

21.20 cm² * 6 tiles = 127.20 cm²  ARea of the hexagon.


7 0
4 years ago
Can someone please help me on this problem? I need help on it please!!
8_murik_8 [283]

Answer:

60 m/h

Step-by-step explanation:

1. the basic formula is Time=Distance/Speed;

2. total time is time1 (for 84 miles)+time2 (for 130 miles)=time (4 hours);

3. the time for the first 84 mi. is time1=84/S;

4. the time for the rest 130 mi. is time2=130/(S-10);

5. using all the data of items 2-4, it is possible to substitute into the basic formula and resolve an equation:

\frac{84}{s} +\frac{130}{s-10} =4; \ => \ 2s^2-127s+420=0;

\left[\begin{array}{ccc}s=60\\s=3.5\end{array}

note, that the value of speed has one condition: s>10. It means, the only value is true: 60 miles per hour.

7 0
3 years ago
What is the formula of volume ofba rhombic prism
Dimas [21]
Volume=the\ base\ area\ multiplied\ by\ the\ height\\\\if\ the\ base\ is\ a\ rhombus,\ \ then\ the\ base\ area= \frac{1}{2}\cdot e\cdot f \ \ \\\\and\ \ \ e,f\rightarrow\ the\ length\ of\ the diagonals\ of\ a\ rhombus\\\\V=\frac{1}{2}\cdot e\cdot f \cdot h\\\\and\ \ h\rightarrow\ the\ height\ of\ prism
8 0
4 years ago
Read 2 more answers
An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
Flura [38]

Answer:

The width of the art projects of area 63.6 square inches is 7.97 inches .

Step-by-step explanation:

Given as :

The area of the square art project = 63.6 square inches

Since The shape of the art project is square

So, The Area of square = A = side × side = side²

Now, let the measure of the width of art project = w inches

I.e side = w inches

or ,  A  = side²

Or , A = w²

Or, 63.6 = w²

So, w = \sqrt{63.6}

I.e w = 7.97 inches

So, the width of the projects = w = 7.97 inches

Hence The width of the art projects of area 63.6 square inches is 7.97 inches . Answer

4 0
4 years ago
Other questions:
  • What is the absolute value of 9.8 and -10/3
    6·2 answers
  • If 100 miles is 20 in. What is the scale factor?
    14·1 answer
  • If the measurement of angle abc=4x+16 and the measurement of angle cbx=3x+6, find the value of X
    15·1 answer
  • Can someone help me with this<br><br>25t = 5( 5t + 1)
    11·1 answer
  • Easy Twist Widgets has some inventory in stock that has been discontinued. The store is taking a 10 cent loss per widget on 125
    15·1 answer
  • HELP SOMEONE PLEASE IGHHH
    11·1 answer
  • Mercury and venus are the sun than earth is.
    7·2 answers
  • Find does angles <br> Help pls I have 15 min only .
    12·2 answers
  • Find the second, fourth, and eleventh terms of the sequence A(n) = 5 + (n - 1)(-3)​
    11·1 answer
  • 2a +7= 15 answer please
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!