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svetlana [45]
3 years ago
11

Find the second, fourth, and eleventh terms of the sequence A(n) = 5 + (n - 1)(-3)​

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer:

2nd: 2

4th: -4

11th: -25

Step-by-step explanation:

When you substitute a number into the equation you get that number term. So, if you substituted in 1, you get the first term. To find the second term, you substitute in 2:

A(2) = 5 + (2 - 1)(-3)

A(2) = 5 + (1)(-3)

A(2) = 5 - 3

A(2) = 2

To get the 4th term you substitute in 4:

A(4) = 5 + (4 - 1)(-3)

A(4) = 5 + (3)(-3)

A(4) = 5 - 9

A(4) = -4

And we do the same for the 11th term:

A(11) = 5 + (11 - 1)(-3)

A(11) = 5 + (10)(-3)

A(11) = 5 - 30

A(11) = -25

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Answer:

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The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

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By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

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In our exercise, the interest rate is 9%. So, by the rule of 72:

D = \frac{72}{9} = 8.

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

A = P(1 + \frac{r}{n})^{nt}

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

A = 2P

r = 0.09

The interest is compounded anually, so n = 1

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.09}{1})^{t}

2 = (1.09)^{t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.09}(1.09)^{t} = \log_{1.09} 2

t = 8.04

The exact doubling time of this amount is 8.04 years.

4 0
4 years ago
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<h3>Answer:</h3>

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