Answer:
or 
Given expression:
Simplify it in steps below:
<u>Used properties:</u>



I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take

, so that

and we're left with the ODE linear in

:

Now suppose

has a power series expansion



Then the ODE can be written as


![\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bn%5Cge2%7D%5Cbigg%5Bn%28n-1%29a_n-%28n-1%29a_%7Bn-1%7D%5Cbigg%5Dx%5E%7Bn-2%7D%3D0)
All the coefficients of the series vanish, and setting

in the power series forms for

and

tell us that

and

, so we get the recurrence

We can solve explicitly for

quite easily:

and so on. Continuing in this way we end up with

so that the solution to the ODE is

We also require the solution to satisfy

, which we can do easily by adding and subtracting a constant as needed:
its the first 1. b.
Step-by-step explanation:
nb. b. b b b bcbcbc
Answer:
12.5%
Step-by-step explanation:
105 over 120 is the fraction that he got so you subtract 105 from 120 to get how much he missed. 120-105=15
He miscalculated by 15 cm out of the total of 120, 15/ 120
15/120=5/40=2.5/20 multiply the top and bottom by 5 to get the percentage out of 100. 2.5 times 5 =12.5, so he miscalculated by 12.5%